0
我正在研究一个允许用户对食谱评分的项目。我做了一个简单的连接表(RecipeRating),用户和配方都共享,但ActiveRecord无法保存。ActiveRecord无法保存记录:“零长度分隔标识符”
@rating = @user.recipe_ratings.where(:recipe_id => @recipe.id).first
@rating.rating = params[:rating]
@rating.save
产量:
ActiveRecord::StatementInvalid in UsersController#rate_recipe
PG::Error: ERROR: zero-length delimited identifier at or near """"
LINE 1: ...013-08-07 14:28:39.965953' WHERE "recipe_ratings"."" IS NULL
^
: UPDATE "recipe_ratings" SET "rating" = 3, "updated_at" = '2013-08-07 14:28:39.965953' WHERE "recipe_ratings"."" IS NULL
显然,错误是由WHERE "recipe_ratings"."" IS NULL
引起的,但什么原因造成这一点,我该如何解决?作为参考,它创建或找到评级没有问题(在我的数据库中按预期保存),它只是无法更新它们。
参考:
class User < ActiveRecord::Base
...
has_many :recipe_ratings
end
class Recipe < ActiveRecord::Base
...
has_many :recipe_ratings
end
class RecipeRating < ActiveRecord::Base
belongs_to :recipe
belongs_to :user
attr_accessible :comment, :rating, :user, :recipe#, :user_id, :recipe_id
end
试试这个,以防万一:'@rating = @ user.recipe_ratings.find_by_recipe_id(@ recipe.id)' – Raindal