VBA运行时错误91 - 2

我有一个宏为前36行工作，但然后显示运行时91错误。它显示find语句中的错误。宏的目的是计算列中数据的第90百分位数，计算等于或大于百分位的值的数量，并提供各部门之间的划分。任何人都可以帮我纠正错误吗？VBA运行时错误91 - 2

For bb = 1 To temcnt 
cc = Sheets("tem").Cells(bb, ttc + 4).Value 
Sheets("Geographic Strength").Activate 
Cells.Find(What:=cc, After:=ActiveCell, LookIn:=xlFormulas, LookAt _ 
    :=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ 
    False, SearchFormat:=False).Activate 

    ff1 = ActiveCell.Column 
    Sheets("tem").Activate 
    rnggg = Range(Cells(2, 6), Cells(ttr, 6)) 
    mamm = WorksheetFunction.CountIf(Range(Cells(2, 6), Cells(ttr, 6)), cc) 
Sheets("geographic strength").Activate 
f222 = Sheets("individual strength").Cells(1, iii).Value 

**Cells.Find(What:=f222, After:=ActiveCell, LookIn:=xlFormulas, LookAt _ 
    :=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ 
    False, SearchFormat:=False).Activate 
    f333 = ActiveCell.Row** 

'Error is in the above statement(Cells.Find) 

Cells(f333, ff1).Value = mamm 
Next bb 
Sheets("tem").Delete 
Next iii 
Application.DisplayAlerts = True 
Application.ScreenUpdating = True 
End Sub

来源

2016-10-17 Jagpreet Singh Bhatia

使用'.Activate'，'.Select'等通常是一个坏主意b因为它会放慢宏观并增加犯错的风险。 [Here]（http://stackoverflow.com/questions/10714251/how-to-avoid-using-select-in-excel-vba-macros）和[here]（http://stackoverflow.com/documentation/excel -vba/1107/vba-best-practices/9292/avoid-using-select-or-activate）是如何避免它的一些提示。 – arcadeprecinct

这是因为

Cells.Find(What:=f222, After:=ActiveCell, LookIn:=xlFormulas, LookAt _ 
    :=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ 
    False, SearchFormat:=False)

没有找到想要的细胞，因此返回Nothing成功，你不能ActivateNothing

，所以你可以去像如下：

'... your code before 
f222 = Sheets("individual strength").Cells(1, iii).Value 

Dim found As Range 
Set found = Cells.Find(What:=f222, After:=ActiveCell, LookIn:=xlFormulas, LookAt _ 
:=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:= _ 
False, SearchFormat:=False) 

If Not found Is Nothing Then '<-- check if any cell has been found 
    found.Activate 
    f333 = ActiveCell.Row 

    '... rest of your code should f222 have been found 

End If 

' rest of your code

来源

2016-10-17 06:42:02 user3598756

非常感谢您的帮助。它现在正在完美工作。 :) –

VBA运行时错误91 - 2

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