2011-01-30 66 views

回答

2

这绝对简单,如果你使用:

SELECT hour(timediff('2011-01-26 23:51:20', 
        '2011-01-26 15:51:10')) 
    AS totalhours 
0

使用timetosec,其他方法总是给你一个积极的结果...即

SELECT 
     (hour(
      timediff('2011-01-29 23:51:20', 
        '2011-01-26 15:51:10') 
      )) 
    AS totalhours 

=80 

SELECT 
     (hour(
      timediff('2011-01-26 23:51:20', 
        '2011-01-29 15:51:10') 
      )) 
    AS totalhours 

= 63 
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