3个表格的左外连接

Question

我试图获得阴影区域的不同人数。

表结构如下：

customer  key 
    A234   1 
    A345   4 
    A12    5 
    A989   6 

HIVE查询：

select count(distinct(a.customer)) 
    from (
     select * 
     from cust 
     where key in (1,2,3)) c 
    left outer join (
     select * 
     from cust 
     where key in (4,5)) a on a.customer= c.customer where c.customer is null 
     join 
      (select * 
      from cust 
      where key in (6,7,8,9)) d on c.customer = d.customer and d.customer is null; 

错误：

在缺少EOF '加入' 接近 '零'

Answer 1

由于where遵循from子句，并且给定的select只有一个where，所以存在语法问题。我想用group by和having。为了让客户：

select c.customer 
from cust c 
group by c.customer 
having sum(case when key in (1, 2, 3) then 1 else 0 end) > 0 and 
     sum(case when key in (4, 5, 6, 7, 8, 9) then 1 else 0 end) = 0; 

然后，您可以使用子查询数得过来：

select count(*) 
from (select c.customer 
     from cust c 
     group by c.customer 
     having sum(case when key in (1, 2, 3) then 1 else 0 end) > 0 and 
      sum(case when key in (4, 5, 6, 7, 8, 9) then 1 else 0 end) = 0 
    ) c