如何使用Python套接字发送SIP消息

我需要使用Python套接字发送SIP消息，我已经让客户端向服务器发送了一些消息，但是我无法让该客户端向服务器发送SIP消息INVITE如何使用Python套接字发送SIP消息

#!/usr/bin/python 

import socket 

R_IP = '192.168.2.1' 
R_PORT = 5060 

message = 'INVITE sip:[email protected] SIP/2.0 To: <sip:[email protected]>\x0d\x0aFrom: sip:[email protected];tag=R400_BAD_REQUEST;taag=4488.1908442942.0\x0d\x0aP-Served-User: sip:[email protected]\x0d\x0aCall-ID: [email protected]\x0d\x0aCSeq: 1 INVITE\x0d\x0aContact: sip:[email protected]\x0d\x0aMax-Forwards: 70\x0d\x0aVia: SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\x0d\x0aContent-Length: 10\x0d\x0a\x0d\x0aRandomText' 

def sendPacket(): 
    proto = socket.getprotobyname('tcp')       
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)#, proto) 

    try: 
     s.connect((R_IP , R_PORT)) 
     s.sendall(message)          
    except socket.error: 
     pass 
    finally: 
     s.close() 

sendPacket()

你有什么想法吗？

来源

2017-02-09 Damian Silkowski

好吧，我知道，meybe它会帮助别人。

正确的格式SIP消息如下：

INVITE sip:[email protected] SIP/2.0 
To: <to> 
Call-ID: <call_id> 
<empty line> 
body

所以，

message = 'INVITE sip:[email protected] SIP/2.0\r\nTo: <sip:[email protected]>\r\nFroma: sip:[email protected];tag=R400_BAD_REQUEST;taag=4488.1908442942.0\r\nP-Served-User: sip:[email protected]\r\nCall-ID: [email protected]\r\nCSeq: 1 INVITE\r\nContact: sip:[email protected]\r\nMax-Forwards: 70\r\nVia: SIP/2.0/TCP 10.44.40.47;branch=z9hG4bK1908442942.4488.0\r\nContent-Length: 10\r\n\r\nRandomText'

\r\n是非常重要的，而不空的空间

来源

2017-02-09 13:35:07

如何使用Python套接字发送SIP消息

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