jQuery的自动完成功能显示了两个从MySQL行一行

Question

我有一个MySQL表，多行

ID, country, city, region 

我有一个搜索使用jQuery UI的自动完成，目前自动填充城市的搜索量，像这样的工作：

if (isset($_GET['term'])){ 
    $return_arr = array(); 

    try { 
     $conn = new PDO("mysql:host=".DB_SERVER.";port=8889;dbname=".DB_NAME, DB_USER, DB_PASSWORD); 
     $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

     $stmt = $conn->prepare('SELECT city,country FROM location WHERE city LIKE :term LIMIT 10'); 
     $stmt->execute(array('term' => '%'.$_GET['term'].'%')); 

     while($row = $stmt->fetch()) { 
      $return_arr[] = $row['city']; 

     } 

    } catch(PDOException $e) { 
     echo 'ERROR: ' . $e->getMessage(); 
    } 



    echo json_encode($return_arr); 
} 

我想显示该国城旁，所以Los Angeles将成为Los Angeles, US

Answer 1

在PHP中可以通过使用附加的字符串“ “。例如：！

$mystring = 'part one' . 'part two'; 

echo $mystring; //-> will product: part onepart wo 

您也可以让PHP解释一个字符串，用'“（双引号）的限定

$myvar = "boat"; 
$mystring = "One day I'll buy a {$myvar}"; 

echo $mystring; //-> will produce: One day I'll buy a boat 

下面应该工作正常好运

if (isset($_GET['term'])){ 
    $return_arr = array(); 

    try { 
     $conn = new PDO("mysql:host=".DB_SERVER.";port=8889;dbname=".DB_NAME, DB_USER, DB_PASSWORD); 
     $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

     $stmt = $conn->prepare('SELECT city,country FROM location WHERE city LIKE :term LIMIT 10'); 
     $stmt->execute(array('term' => '%'.$_GET['term'].'%')); 

     while($row = $stmt->fetch()) { 
      $return_arr[] = $row['city'] . ', ' . $row['country']; 

     } 

    } catch(PDOException $e) { 
     echo 'ERROR: ' . $e->getMessage(); 
    } 



    echo json_encode($return_arr); 
} 

解决这个问题的另一种方法是在SQL中追加字符串

SELECT CONCAT(city, ', ', country) AS location FROM location WHERE city LIKE :term LIMIT 10