令牌上的语法错误“;”在Java

Question

“令牌上的语法错误”;“，此令牌后预期的原语类型”是我在这条语句"String data = input.next(); "上的分号后得到的消息，我不知道为什么。

import java.util.*; 
public class PorterHouse { 
    public static void main(String[] args){ 
System.out.println("enter interest rate, loan mount, and number of years: ex. "+ 
    " 7.9-400000-5"); 
Scanner input = new Scanner(System.in); 

String data = input.next(); 

[] b = data.split("[-]"); 
double interstRate = Double.parseDouble(b[0]); 
double loanPrincipal = Double.parseDouble(b[1]); 
double loanLength = Double.parseDouble(b[2]); 
double monthlyPayment = (b[1]*b[2]/1); 
double totalPayment = (monthlyPayment * loanLength * 12); 
System.out.println("Monthly Pament: " + monthlyPayment); 
System.out.println("totalPayment: " + totalPayment); 


} 
} 

Answer 1

试图改变这一点：

[] b = data.split("[-]"); 

与此：

string[] b = data.split("[-]"); 

目前[] b没有数据类型。所以请给它提供一个数据类型。

Answer 2

我想，而不是：

[] b = data.split("[-]"); 

你需要的东西，如：

String[] b = data.split("[-]"); 

也

你可能想更换：

double monthlyPayment = (b[1]*b[2]/1); 

由：

double monthlyPayment = (loanPrincipal * loanLength/1); //idk why divide by 1?? 

cuz，b[1]和b[2]是两个字符串。