水平字符串连接有内置函数吗？

Question

给定两个文件：

File1中

A A A
B B B
C C C

文件2

d d
ëë

Bash有以水平串连这些文件的命令：

paste File1 File2 

aaadd
bbbee
CCC

C＃有一个内置的功能，其行为像这样？

Answer 1

public void ConcatStreams(TextReader left, TextReader right, TextWriter output, string separator = " ") 
{ 
    while (true) 
    { 
     string leftLine = left.ReadLine(); 
     string rightLine = right.ReadLine(); 
     if (leftLine == null && rightLine == null) 
      return; 

     output.Write((leftLine ?? "")); 
     output.Write(separator); 
     output.WriteLine((rightLine ?? "")); 
    } 
} 

使用例：

StringReader a = new StringReader(@"a a a 
b b b 
c c c"; 
StringReader b = new StringReader(@"d d 
e e"; 

StringWriter c = new StringWriter(); 
ConcatStreams(a, b, c); 
Console.WriteLine(c.ToString()); 
// a a a d d 
// b b b e e 
// c c c 

Answer 2

不幸的是，Zip()想要的文件与等于长度，所以在情况下的LINQ你必须实现类似的东西：

public static EnumerableExtensions { 
    public static IEnumerable<TResult> Merge<TFirst, TSecond, TResult>(
    this IEnumerable<TFirst> first, 
    IEnumerable<TSecond> second, 
    Func<TFirst, TSecond, TResult> map) { 

     if (null == first) 
     throw new ArgumentNullException("first"); 
     else if (null == second) 
     throw new ArgumentNullException("second"); 
     else if (null == map) 
     throw new ArgumentNullException("map"); 

     using (var enFirst = first.GetEnumerator()) { 
     using (var enSecond = second.GetEnumerator()) { 
      while (enFirst.MoveNext()) 
      if (enSecond.MoveNext()) 
       yield return map(enFirst.Current, enSecond.Current); 
      else 
       yield return map(enFirst.Current, default(TSecond)); 

      while (enSecond.MoveNext()) 
      yield return map(default(TFirst), enSecond.Current); 
     } 
     } 
    } 
    } 
} 

有Merge扩展方法，你可以把

var result = File 
    .ReadLines(@"C:\First.txt") 
    .Merge(File.ReadLines(@"C:\Second.txt"), 
     (line1, line2) => line1 + " " + line2); 

File.WriteAllLines(@"C:\CombinedFile.txt", result); 

// To test 
Console.Write(String.Join(Environment.NewLine, result));