如何检查两个字符串是否包含相同的字母？

Question

$textone = "pate"; //$_GET 
$texttwo = "tape"; 
$texttre = "tapp"; 

if ($textone ??? $texttwo) { 
echo "The two strings contain the same letters"; 
} 
if ($textone ??? $texttre) { 
echo "The two strings NOT contain the same letters"; 
} 

什么if声明我在找什么？

Answer 1

我想一个解决办法是，考虑到以下两个变量：

$textone = "pate"; 
$texttwo = "tape"; 

1.首先，分割字符串，得到的字母两个数组：

$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY); 
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY); 

需要注意的是，在他的评论中指出@Mike，而不是使用preg_split()像我第一次做，对于这样的情况，人们将使用str_split()会更好：

$arr1 = str_split($textone); 
$arr2 = str_split($texttwo); 

2.然后，排序的那些阵列，所以字母按字母顺序排列：

sort($arr1); 
sort($arr2); 

之后，破灭的阵列，打造话所有的字母按字母顺序排列：

$text1Sorted = implode('', $arr1); 
$text2Sorted = implode('', $arr2); 

4.最后，比较这些两个单词：

if ($text1Sorted == $text2Sorted) { 
    echo "$text1Sorted == $text2Sorted"; 
} 
else { 
    echo "$text1Sorted != $text2Sorted"; 
} 

---

谈到这个想法变成一个比较函数会给你的代码如下部分：

function compare($textone, $texttwo) { 
    $arr1 = str_split($textone); 
    $arr2 = str_split($texttwo); 

    sort($arr1); 
    sort($arr2); 

    $text1Sorted = implode('', $arr1); 
    $text2Sorted = implode('', $arr2); 

    if ($text1Sorted == $text2Sorted) { 
     echo "$text1Sorted == $text2Sorted<br />"; 
    } 
    else { 
     echo "$text1Sorted != $text2Sorted<br />"; 
    } 
} 

并呼吁你的两个话该功能：

compare("pate", "tape"); 
compare("pate", "tapp"); 

会得到你以下结果：

aept == aept 
aept != appt 

Answer 2

使用===和!==

if ($textone === $texttwo) { 
    echo "The two strings contain the same letters"; 
}else{ 
    echo "The two strings NOT contain the same letters"; 
} 

或

if ($textone === $texttwo) { 
    echo "The two strings contain the same letters"; 
} 

if ($textone !== $texttwo) { 
    echo "The two strings NOT contain the same letters"; 
}