2014-10-05 25 views
1

说,我有表上的MySQL名为tbl_order像这样(只图)结构:如何选择以前的记录不取决于在MySQL中的AutoIncrements ID?

 
--------------------------------------------------------------------------------------------------------- 
| id | grade | type | order_date   | order_confim_time | vol_in | vol_out | vol_dev | status | 
| AI | VARCH | VARCH | TIMESTAMP   | TIMESTAMP   | DOUBLE | DOUBLE | DOUBLE | VARCH | 
--------------------------------------------------------------------------------------------------------- 
| 81 | AAA | IN | 2014-09-10 09:00:00 | 2014-09-10 13:00:00 | 498000 |  0 | -2000 | CONFIRM | 
| 83 | AAA | IN | 2014-09-10 10:01:00 | 2014-09-10 14:00:00 | 998000 |  0 | -2000 | CONFIRM | 
| 85 | AAA | OUT | 2014-09-11 09:02:00 | 2014-09-11 13:00:00 |  0 | 99000 | -1000 | CONFIRM | 
| 87 | AAA | OUT | 2014-09-11 10:03:00 | 2014-09-11 14:00:00 |  0 | 145000 | -5000 | CONFIRM | 
| 89 | AAA | OUT | 2014-09-12 09:04:00 | 2014-09-12 13:00:00 |  0 | 120000 | -5000 | CONFIRM | 
| 91 | AAA | OUT | 2014-09-12 09:06:00 | NULL    |  0 | 130000 | -2000 | NOTCONF | 
| 93 | AAA | OUT | 2014-09-13 10:05:00 | 2014-09-12 14:00:00 |  0 | 115000 | -5000 | CONFIRM | 
--------------------------------------------------------------------------------------------------------- 

然后我做了以下查询:

SELECT * FROM `tbl_order` WHERE `tbl_order`.`grade` = 'AAA' AND `tbl_order`.`order_confim_time` < NOW() ORDER BY `tbl_order`.`status` DESC, `tbl_order`.`order_confim_time` ASC 

所以,在我们可以得到以下结果:

 
--------------------------------------------------------------------------------------------------------- 
| id | grade | type | order_date   | order_confim_time | vol_in | vol_out | vol_dev | status | 
| AI | VARCH | VARCH | TIMESTAMP   | TIMESTAMP   | DOUBLE | DOUBLE | DOUBLE | VARCH | 
--------------------------------------------------------------------------------------------------------- 
| 91 | AAA | OUT | 2014-09-12 09:06:00 | NULL    |  0 | 130000 | -2000 | NOTCONF | 
| 93 | AAA | OUT | 2014-09-13 10:05:00 | 2014-09-12 14:00:00 |  0 | 115000 | -5000 | CONFIRM | 
| 89 | AAA | OUT | 2014-09-12 09:04:00 | 2014-09-12 13:00:00 |  0 | 120000 | -5000 | CONFIRM | 
| 87 | AAA | OUT | 2014-09-11 10:03:00 | 2014-09-11 14:00:00 |  0 | 145000 | -5000 | CONFIRM | 
| 85 | AAA | OUT | 2014-09-11 09:02:00 | 2014-09-11 13:00:00 |  0 | 99000 | -1000 | CONFIRM | 
| 83 | AAA | IN | 2014-09-10 10:01:00 | 2014-09-10 14:00:00 | 998000 |  0 | -2000 | CONFIRM | 
| 81 | AAA | IN | 2014-09-10 09:00:00 | 2014-09-10 13:00:00 | 498000 |  0 | -2000 | CONFIRM | 
--------------------------------------------------------------------------------------------------------- 

我为了写下面的函数在我的模型Order用递归以获得上一行:

 

    // i made simplify code, but still the code only work on 1st previous row. the rest still not. 
    public function getPrevRow() { 
    if (is_null($this->order_confim_time)) 
     { 
      $data = self::model()->find(array(
       'condition' => '`t`.`grade`=:type_order AND (`t`.`order_date` '`t`.`status` DESC, `t`.`order_confim_time` DESC, `t`.`id` DESC', 
       'limit'  => 1, 
       'params' => array('type_order' => $this->grade, ':current_date_confirm' => $this->order_confim_time), 
      )); 

      if (is_null($data)) return 0; 
      else return floatval($data->PrevRow) + 
      floatval($data->vol_in) + 
      floatval($data->vol_dev) - 
      floatval($data->vol_out); 
     } else { 
      $data = self::model()->find(array(
       'condition' => '`t`.`order_confim_time` '`t`.`status` DESC, `t`.`id` DESC', 
       'limit'  => 1, 
       'params' => array(':current_date_confirm' => $this->order_confim_time, 'type_order' => $this->grade), 
      )); 

      if (is_null($data)) return 0; 
      else return floatval($data->PrevRow) + 
      floatval($data->vol_in) + 
      floatval($data->vol_dev) - 
      floatval($data->vol_out); 
     } 
    } 

结果相当不错,只有尊重order_confirm_timeNOT NULL值。

Current result in CGridView

The expected condition is something like this

我怎样才能上一行而不需要依赖于ORDER BY id DESC?目前我依赖于ORDER BY order_confirm_time

我使用Yii 1.1.16分支,PHP 5.4 @ Windows 7的64位,MariaDB的38年5月5日

+0

我不明白你的问题“我怎样才能得到与ID = 93行无需取决于ORDER BY ID DESC”,你可以只发布你想要得到的输出? – 2014-10-05 19:05:02

+0

@ brian-demilia,对不起,如果我的问题不清楚。目标/预期的结果是我可以得到以前的行ID而不依赖于'id'字段。目前我使用'ORDER BY order_confim_time',但只显示不为空(带有值的order_confim_time)数据。 请看看这张照片[当前情况](http://imgbox.com/SKf73tAy)。有2个圆圈,红色和绿色。我想做出这样的[预期条件](http://imgbox.com/ocnyOCha)。 – agungandika 2014-10-05 19:41:07

+0

@Brian德米莉亚,对我的案件的任何想法?我已经简化了我的代码,但仍然只有第一行。其余的仍然指向前一行。 – agungandika 2014-10-05 19:59:22

回答

0

在伪代码,你可以这样做:

  1. 初始化tempv_var
  2. 通过记录你的my_array
  3. 存储RECO之前初始化my_array
  4. 循环您的记录
  5. 做一些条件,在这里在my_array [temp_var]
  6. 增量temp_var

在结束RDS你有你的my_array是内容与temp_var的索引记录。这是直接的解决方案,但您可以在SQL查询中执行此操作,并在脚本中添加一些逻辑。