排序列表

Question

的元素我有一个列表

str(overlaps) 
List of 7 
$ a5: chr [1:6] "calc_a1c" "predmdx_flag" "bmi" "systolic" ... 
$ a2: chr [1:2] "age" "yr" 
$ a4: chr(0) 
$ a6: chr(0) 
$ a1: chr [1:2] "trig_3cat" "glipizide_flag" 
$ a3: chr [1:2] "email_flag" "statins_flag" 
$ a7: chr [1:4] "trig_3cat.>=200" "antihtn_flag" "black_flag" "gender.M" 

我要重新排序列表，使得结果列表是一个其中的元素按数字顺序排列。即A1，A2，A3等

Answer 1

一些随机数据：

set.seed(42) 
overlaps <- replicate(5, runif(3), simplify=FALSE) 
names(overlaps) <- paste0("a", sample(5)) 
str(overlaps) 
# List of 5 
# $ a5: num [1:3] 0.915 0.937 0.286 
# $ a4: num [1:3] 0.83 0.642 0.519 
# $ a1: num [1:3] 0.737 0.135 0.657 
# $ a3: num [1:3] 0.705 0.458 0.719 
# $ a2: num [1:3] 0.935 0.255 0.462 

排序：

str(overlaps[ sort(names(overlaps)) ]) 
# List of 5 
# $ a1: num [1:3] 0.737 0.135 0.657 
# $ a2: num [1:3] 0.935 0.255 0.462 
# $ a3: num [1:3] 0.705 0.458 0.719 
# $ a4: num [1:3] 0.83 0.642 0.519 
# $ a5: num [1:3] 0.915 0.937 0.286 

Answer 2

这是为了r2evans'答案，这是优良的选择。我用他的示例数据集。

str(overlaps[order(names(overlaps))]) 

#List of 5 
# $ a1: num [1:3] 0.737 0.135 0.657 
# $ a2: num [1:3] 0.935 0.255 0.462 
# $ a3: num [1:3] 0.705 0.458 0.719 
# $ a4: num [1:3] 0.83 0.642 0.519 
# $ a5: num [1:3] 0.915 0.937 0.286