到PHP变量,这是我的javascript代码:如何传递的值通过AJAX
function category(row){
dataparam = "oper=delete&row="+row;
$.ajax({
type: "POST",
url: "multiupload.php",
data: dataparam,
error:function() {
alert("sorry")
},
success: function(html) {
alert(html);
}
});
}
和我的PHP脚本:
$opers = (isset($_REQUEST['opers']) and $_REQUEST['opers'] != '') ? $_REQUEST['opers'] : '';
if($opers == "delete") {
$row=$_REQUEST['row'];
echo $row;
}
这是不工作...我不知道什么问题是。请帮我在我的php脚本中获取$row
变量。
可能的重复http://stackoverflow.com/questions/6130662/passing-javascript-variable-to-php-using-ajax/? – Liam 2011-05-26 13:58:25