Flex：中心窗口？

Question

我想在flex中居中启动的窗口，有一个NativeWindow.x和NativeWindow.y，但flex使用Window类没有这些属性，所以没有人知道如何居中窗口？谢谢！！

Answer 1

我想通了：

window.nativeWindow.x = (Screen.mainScreen.bounds.width - window.width)/2; 
window.nativeWindow.y = (Screen.mainScreen.bounds.height - window.height)/2; 

我认为你必须调用这个window.open（）后虽然。

Answer 2

是不是更好？

例如文档：

// center the window on the screen 
var screenBounds:Rectangle = Screen.mainScreen.bounds; 
nativeWindow.x = (screenBounds.width - nativeWindow.width)/2; 
nativeWindow.y = (screenBounds.height - nativeWindow.height)/2; 

from livedocs: about window containers ¨

两个解决方案为我工作，即使在多屏系统（Win7的）

Answer 3

其实这个工作更好的柔性4.5及以上

nativeWindow.x = (Screen.mainScreen.bounds.width - nativeWindow.width)/2; 
nativeWindow.y = (Screen.mainScreen.bounds.height - nativeWindow.height)/2; 

Answer 4

这就是我用的

nativeWindow.x = (Capabilities.screenResolutionX - nativeWindow.width)/2; nativeWindow.y = (Capabilities.screenResolutionY - nativeWindow.height)/2;

似乎运作良好