Dataweave：获取，而不是字符串

Question

com.mulesoft.weave.model.structure.QualifiedName我有一个数据库查询，像这样返回数据：

"LABEL","CONTAINER_ID","STATUS" 
"14.JW24","1006063116","F" 
"14.JW25","1006063116","F" 
"1.JW2M","9999997","R" 
"8.282","9999999","R" 
"4.135","9999999","F" 
"6.43","9999999","F" 
"11.12","9999999","R" 
"14.JW12","1006063073","R" 
"14.JW13","1006063073","R" 
"14.JW10","1006063068","F" 

我使用Dataweave创建不同的列表具有“F”状态的container_id值。喜欢的东西：

["1006063116", "9999999", "1006063068"] 

这里是我的dataweave脚本：

%dw 1.0 
%output application/java 
--- 
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ 

，我得到com.mulesoft.weave.model.structure.QualifiedName对象的列表，而不是名单这工作，除了罚款字符串。

我该如何修改dataweave脚本才能获取字符串，或者，如何从QualifiedName对象获取字符串值？我试过在对象上调用toString（）和getName（）。前者不给我需要的价值，后者不起作用。

Answer 1

只投，结果元素串这样的：

%dw 1.0 
%output application/java 
--- 
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ as :string 

的重要组成部分，是as :string

替代解决方案：您可以使用distinctBy关键字来实现类似的结果，并摆脱GROUPBY +勇气的：

%dw 1.0 
%output application/java 
--- 
(payload filter $.status == "F").container_id distinctBy $