使用脚本应用从Google表格中的单元格拉取日期

Question

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我的小型企业使用QuickBooks进行工资计时，但出于后勤目的，我们的员工使用谷歌电子表格输入他们的时间。

我想写一个脚本，每天检查第一列的日期两次（按照我设置的触发器）。如果日期等于或大于今天的日期，我需要脚本检查同一行中几列的单元格以查看单元格是否已被填写。如果它是0或null，我想发送一个通知。

请参阅下图以供参考。

Test

到目前为止，这是我所：

function values2() 
{ 
    var ss = SpreadsheetApp.getActiveSpreadsheet(), 
     sheet = ss.getSheetByName("TimeSheet"), 
     range = sheet.getDataRange(), 
     values = range.getValues(), 
     indx, logToday, today, body, 
     recipients = "xxxxx@xxx.zzz", 
     subject = "Timesheet Notification" + ss.getName(); 

//Finds current date and creates string. I would prefer to have a numeric value associated to the current date, as well as a numeric value associated with the date for each row. 
    var CurrentDate = new Date(); 
    Logger.log(CurrentDate); 
     logToday = Logger.getLog(); 
     indx = logToday.indexOf("INFO"); 
     today = logToday.substring(indx + 6, indx + 16); 

//I'm having things sent to my email for test purposes 
    MailApp.sendEmail(recipients, subject, today); 
//Clears Log 
    Logger.clear(); 
    for (var r=1; r<values.length; r++) 
    { 
    var row = values[r], 
     date = row[0], 
     price = row[1], 
     units = row[2], 
     total = row[3], 
     name = row[4]; 

    Logger.log(date); 
    Logger.log(price); 
    Logger.log(units), 
    Logger.log(total), 
    Logger.log(name); 
    } 

    body = Logger.getLog(); 
    MailApp.sendEmail(recipients, subject, body); 
} 

在这一点上，我希望能够赶上从第一列每个日期，将其比作今天的日期，支票另一个单元格放在同一行中，然后移至第一列中的下一个日期。我已经玩过IF/Else的声明，但无济于事。

Answer 1

如果你想比较第一列包含空单元格的日期元素到今天，那么下面的脚本怎么样？

function values2() 
{ 
    var ss = SpreadsheetApp.getActiveSpreadsheet(), 
     sheet = ss.getSheetByName("TimeSheet"), 
     range = sheet.getDataRange(), 
     values = range.getValues(), 
     indx, logToday, today, body, 
     recipients = "xxxxx@xxx.zzz", 
     subject = "Timesheet Notification" + ss.getName(); 

    var lR = sheet.getLastRow(); 
    var dateinfo = sheet.getRange('a1').offset(0, 0, lR, 1).getValues(); 
    var today = new Date(); 
    var y0 = today.getFullYear(); 
    var m0 = today.getMonth() + 1; 
    var d0 = today.getDate(); 

    for (var i=0; i<dateinfo.length; i++){ 
     x = Date.parse(dateinfo[i]); 
     var date = new Date(x); 
     var y = date.getFullYear(); 
     var m = date.getMonth() + 1; 
     var d = date.getDate(); 
     if (y0 === y && m0 === m && d0 === d) { 
      Logger.log("ok:" + i) // same date 
     } else { 
      Logger.log("error:" + i) // difference date 
     }; 
    }; 
}