使用d3.json从PHP输出JSON

我创建了一个PHP文件来查询JSON输出。从PHP文件输出JSON特定滤镜“testPHP.php？数= 123”是使用d3.json从PHP输出JSON

[{"source":"AB","target":"AC","type":"true"},{"source":"UB","target":"EP","type":"true"},{"source":"US","target":"UR","type":"lie"},{"source":"BS","target":"QW","type":"lie"},{"source":"UW","target":"EA","type":"lie"}]

我在HTML文件中尝试过这种读取JSON输出变量

var links; // a global 
d3.json("testPHP.php?number=123", function(error, json) { 
    if (error) return console.warn(error); 
    links = json; 
});

联系，但，似乎数据不存储在链接中。如何将数据存储在var links？

基本上，我想用这个https://gist.github.com/mbostock/1153292中的var links替换为PHP的JSON输出。编辑：或http://localhost:8080是造成这个问题？

来源

2013-05-12 Zero

您的JSON无效。你如何生产这个JSON？数组中的最后一个对象缺少一个引号。 – Brad 2013-05-12 21:33:46

错字错误。现在改变了。 – Zero 2013-05-12 21:50:01

d3.json调用是异步的;在“链接”变量填充之前执行回调后包含的代码。

var links; // a global 
d3.json("testPHP.php?number=123", function(error, json) { 
    if (error) return console.warn(error); 
    links = json; 

    console.log(links); // your links are populated here 

    // include the rest of your app here 
}); 

// links is still undefined here because the success callback hasn't been run yet

来源

2013-05-12 22:30:49

-1

你需要写links = [{"source":"AB","target":"AC","type":"true"},{"source":"UB","target":"EP","type":"true"},{"source":"US","target":"UR","type":"lie"},{"source":"BS","target":"QW","type":"lie"},{"source":"UW,"target":"EA","type":"lie"}]

此时链接将持有该信息。你可能想要考虑一个数组。

来源

2013-05-12 21:34:26 user1890328

我需要使用php文件的json输出！ – Zero 2013-05-12 21:46:11

使用d3.json从PHP输出JSON

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