2017-01-23 27 views
1

我花了一些代码,这应该是工作和看到的desinged它不工作,我 坦率地挣扎着爬什么是错的,我需要填写的所有篮筐,但现在只有第一次得到填补,我是否需要做任何支点?或通过选择摆脱更新? Id'like有相同的5行的Tx,并填写所有篮ALL TxID添加,这个自含以下例子可以说明这一点:与TSQL更新选择加入的问题

SELECT * INTO #lkup FROM (  -- drop table #lkup  -- select * from #lkup 
SELECT 201 Cust_ID, 1 Line, 'Pr1' ProductID UNION 
SELECT 201 Cust_ID, 2 Line, 'Pr20' ProductID UNION 
SELECT 201 Cust_ID, 3 Line, 'Pr333' ProductID  ) g 

SELECT * INTO #tx FROM ( -- drop table #tx  -- select * from #tx 
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12001 TxID UNION 
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12002 TxID UNION 
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12003 TxID UNION 
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12004 TxID UNION 
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12005 TxID ) g 


UPDATE tx 
SET Prod1 = CASE WHEN LINE =1 THEN ProductID END, 
     Prod2 = CASE WHEN LINE =2 THEN ProductID END, 
     Prod3 = CASE WHEN LINE =3 THEN ProductID END 
--- SELECT l.Line, l.ProductID, tx.* 
FROM #tx tx 
JOIN #lkup l ON l.Cust_ID = tx.Cust_ID 

SELECT * FROM #tx   -- update #tx set Prod1 = ' ', Prod2 = ' ', Prod3 = ' ' 
SELECT 'Shouldbe' , '201' CustID, 'Pr1' Prod1, 'Pr20' Prod1, 'Pr333' Prod1, 12001 TxID  -- for each Tx 5 rows Total 
+0

引人入胜。它可能是未定义的(或不确定的)行为。尝试用'RIGHT JOIN'替换更新语句的'JOIN',看看会发生什么。你可以用子查询重写'CASE'东西到'#lkup'吗? – dlatikay

+0

Tx我尝试使用(选择)括号而不是案例,它并没有采取它,可能b'z UPDATE语法。与RIGHT JOIN它现在捕获Prod1和Prod3,但仍然不是Prod2(?)。 –

+0

更正:这实际上有效,但将是我最后的手段,我也有人y篮子,并在真正的设置我嵌套选择JOIN。 UPDATE #tx SET#tx.Prod1 = –

回答

0

您可以使用此代码块。

UPDATE tx 
SET Prod1 = l.ProductID, 
     Prod2 = l2.ProductID, 
     Prod3 = l3.ProductID 
--- SELECT l.Line, l.ProductID, tx.* 
FROM #tx tx 
LEFT JOIN #lkup l ON l.Cust_ID = tx.Cust_ID AND l.Line=1 
LEFT JOIN #lkup l2 ON l2.Cust_ID = tx.Cust_ID AND l2.Line=2 
LEFT JOIN #lkup l3 ON l3.Cust_ID = tx.Cust_ID AND l3.Line=3 
0

问题当然是你要多次更新同一行。这是奇怪的是,它不是一个错误,但如果我理解正确的代码,你可以做这样的事情:

UPDATE tx 
SET tx.Prod1 = L.Prod1, 
    tx.Prod2 = L.Prod2, 
    tx.Prod3 = L.Prod3 
FROM #tx tx 
cross apply (
    SELECT 
     Cust_ID, 
     Prod1 = max(CASE WHEN LINE =1 THEN ProductID END), 
     Prod2 = max(CASE WHEN LINE =2 THEN ProductID END), 
     Prod3 = max(CASE WHEN LINE =3 THEN ProductID END) 
    FROM #lkup 
    group by Cust_ID 
) L where L.Cust_ID = tx.Cust_ID 

结果:

   Cust_ID Prod1 Prod2 Prod3 TxID 
1 201  Pr1  Pr20 Pr333 12001 
2 201  Pr1  Pr20 Pr333 12002 
3 201  Pr1  Pr20 Pr333 12003 
4 201  Pr1  Pr20 Pr333 12004 
5 201  Pr1  Pr20 Pr333 12005