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分层树:找到下一个元素与条件
mouse (depth:0, sequence:0)
* organ system (depth:1, sequence:1)
o visceral organ (depth:2, sequence:2)
urinary system (depth:3, sequence:3)
mesentery (depth:4, sequence:4)
* rest of mesentery (depth:5, sequence:5)
* urogenital mesentery (depth:5, sequence:6)
metanephros (depth:4, sequence:7)
* renal capsule (depth:5, sequence:8)
* nephrogenic zone (depth:5, sequence:9)
我有以下代码选择的节点,它具有相同的深度选择的节点和后应取回第一个节点的名称序列值应大于selected_node_sequence更大:
/** node id has the same value as node_depth **/
var selected_node_depth = parseInt($j(element).attr('APO_DEPTH'));
var selected_node_sequence = parseInt($j(element).attr('APO_SEQUENCE'));
var first_next_node_with_same_depth = $j("#"+selected_node_depth).next().attr("name"); [where first_next_node_with_same_depth sequence value > selected_node_sequence]
例如,如果 'SELECTED_NODE'=肠系膜中, 'first_next_node_with_same_depth' 应该是后肾
关于如何做到这一点的任何建议是最赞赏
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