1
关于连接和null有很多问题,但我无法找到与此特定模式匹配的问题。我有3个非常简单的表格。与NULL连接
+---------+
| service |
+---------+
| id |
| name |
+---------+
+-----------+
| propnames |
+-----------+
| id |
| name |
| sort |
+-----------+
+----------+
| props |
+----------+
| sid |
| pid |
| value |
+----------+
我希望能够添加属性(以propnames)和查询我的服务,我的加盟性质(道具),并知道哪个属性已尚未设置。
如果是这种服务
(id), (name)
1, "AAA"
2, "BBB"
这是propnames
(id), (name), (sort)
1, "property_a", 1
2, "property_b", 2
3, "property_c", 3
这是道具
(service.id), (propname.id), (value)
1, 1, "Service AAA has property_a value"
1, 2, "Service AAA has property_b value"
2, 1, "Service BBB has property_a value"
然后最终我的查询将产生这样的:
(service.id), (service.name), (property.id), (property.name), (props.value)
1, "AAA", 1, "property_a", "Service AAA has property_a value"
1, "AAA", 2, "property_b", "Service AAA has property_b value"
1, "AAA", 3, "property_c", NULL
2, "BBB", 1, "property_a", "Service BBB has property_a value"
2, "BBB", 2, "property_b", NULL
2, "BBB", 3, "property_c", NULL
理想的情况下,它会通过service.name ASC -then- property.sort
进行排序目前不完整的查询是:
SELECT s.id, s.name, p.id, p.name, props.value
FROM service.s
LEFT JOIN propnames p ON s.id = p.sid
LEFT JOIN props ON props.pid = p.id
ORDER BY s.name ASC, p.sort ASC