PHP Comapring数组包含相同的字符串，但不包括相同的行

Question

我有两个数组：

$a = array (

[0] => 0 
[1] => 1 
[2] => 2 
[3] => 3 

) 

$b = array (

[0] => 2 
[1] => 1 
[2] => 3 
[3] => 4 

) 

如果我要算的是同一个对象，我可以用array_intersect - >echo count(array_intersect($a,$b));。 将返回：3

不过，我想他们排除相同的行：

$a = array (

[0] => 0 
[1] => 1 //Both are the same that I would like to exclude 
[2] => 2 
[3] => 3 

) 

$b = array (

[0] => 2 
[1] => 1 //Both are the same that I would like to exclude 
[2] => 3 
[3] => 4 

) 

这只会返回2。

我该怎么做？由于

Answer 1

我会用一个循环，想不出别的现在。

$identical = 0; 
for($i = 0; $i < count($a); $i++) { 
    if(isset($b[$i]) && $a[$i] === $b[$i]) { 
     $identical++; 
    } 
} 
$count = count(array_intersect($a,$b)) - $identical; 
$count = ($count < 0) ? 0 : $count; 
echo $count; 

Answer 2

试试这个

$a = array (0,1,2,3); 
$b = array (2,1,3,4); 

$final = array_unique(array_merge($a,$b)); 

print "total : ". count($final);