2017-06-24 38 views
1

我正在一个简单的test.py应用程序上测试py2app,没有做任何特别的事情。在py2app中的错误

python == 3.6 
py2app == 0.14 

它建立精细,没有错误时,我给这个命令:

python3.6 setup.py py2app -A 

但是当我启动它,这就是结果:

./dist/test.app/Contents/MacOS/test 

Traceback (most recent call last): 
    File "/Users/fabio/projvenv/dist/test.app/Contents/Resources/__boot__.py", line 132, in <module> 
    _run() 
    File "/Users/fabio/projvenv/dist/test.app/Contents/Resources/__boot__.py", line 126, in _run 
    exec(compile(source, script, 'exec'), globals(), globals()) 
    File "/Users/fabio/projvenv/test.py", line 3, in <module> 
    import tkinter 
    File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/tkinter/__init__.py", line 36, in <module> 
    import _tkinter # If this fails your Python may not be configured for Tk 
ValueError: character U+6573552f is not in range [U+0000; U+10ffff] 
2017-06-24 11:32:26.266 test[65341:8804502] test Error 
+1

我最终降级py2app为0.12,并解决了问题 – user7330

回答

2

降级至0.12的固定问题为了我。更多的解决方法,虽然,但我已经足够好,在这一点