如果我有这样的如何根据其中一个对象属性的值从数组中选择一个随机元素?
resources[0] = new Resource("Brick", 0x990000, 3);
resources[1] = new Resource("Wool", 0xFFFFFF, 4);
resources[2] = new Resource("Lumber", 0x006600, 4);
resources[3] = new Resource("Stone", 0x999999, 3);
resources[4] = new Resource("Wheat", 0xFFFF33, 4);
resources[5] = new Resource("Wasteland", 0xcc9966, 1);
数组我如何选择具有大于0的可用性的随机资源?这是我当前的尝试:
int[] diceSpaces = {2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12};
diceSpaces = shuffleArray(diceSpaces);
for(int i = 0; i < diceSpaces.length; i++){
Resource currentResource = null;
for(int r = 0; r < resources.length; r++){
int tryResource = new Random().nextInt(resources.length);
if(diceSpaces[i] != 7){
if(resources[tryResource].available > 0){
currentResource = resources[tryResource];
break;
}
} else {
currentResource = resources[5];
break;
}
}
currentResource.available--;
}
你的代码很混乱......那里面有什么变数?你的意思是r。 – vilpe89
这段代码还有两个循环,因为我没有认为它们是相关的,所以我没有包含这些代码。道歉。 – ShoeLace1291
@ ShoeLace1291什么不工作? – brso05