2013-09-24 43 views
0

我已经创建了两个php文件,其中包含自助餐厅的订单表单以及用于在数据库中插入张贴值的代码的相应代码行。我在这里介绍他们。在数据库中插入复选框和文本框中的数据

FOR addorder_form.php

**<?php 

     db_connect(); 

     $cats=array("Kafedes", "Rofhmata", "Pota", "Snack/Glyka"); 
     $arrlength=count($cats); 

    for($i=0;$i<$arrlength;$i++) { 
     $sql = mysql_query('SELECT title FROM products WHERE cname="'.$cats[$i].'"') or die(mysql_error()); 
     echo '<div id="main_content">'; 
     echo "<h4 style=color:#800000> ".$cats[$i]."</h4>"; 
     echo "<br />"; 


     while($row = mysql_fetch_array($sql, MYSQL_BOTH)){ 
      echo "<div id='center' style='align:center'>"; 
      echo "<input style='text-align:right;' type='checkbox' action='addorder.php' name='products[]' value='".$row["title"]."'>".$row["title"]; 
      echo '</div>'; 

      echo ' <div id="center_side" style="float:right"><form "method="post" action="addorder.php"><input type="text" size="4" padding-left="0.2em" name="quantity"/>'; 
      echo '</div>'; 
     echo '</div>'; 
     echo '<br />'; 
     } 
    } 
    echo '<form name="addorder" method="" action="addorder.php" onclick="addorder.php">'; 
       echo '<input type="submit" value="Add order" style="float: right;"><br/>'; 
       echo '</form>'; 
    ?>** 

CODE码FOR addorder.php

**<?php 
     include_once("buzzcafe_fns.php"); 
     do_html_header(""); 




$quantity = ''; 
$title = ''; 

if (isset($_POST['quantity']) && isset($_POST['products'])) { 
    if(isset($_POST["Submit"])) { 
    $quantity = $_POST['quantity']; 
$title = $_POST['products']; 
if($_POST["Submit"] == "Submit") 
{ 
for ($i=0; $i<sizeof($title); $i++) { 
db_connect(); 
$insertOrder = mysql_query("INSERT INTO orders VALUES('".$title[i]."','".$quantity."')")or die(mysql_error()); 

    } 
echo "Record inserted"; 

} 
} 
} 
?>** 

当我运行他们,我有非任何语法错误,但它不工作。至于在我包含的buzzcafe_fns.php文件中设置了db_connect(),并检查它是否正常工作。我怎样才能让我的“INSERT INTO”工作?

回答

1
You can use another insert query 
First You will check if $title variable array or not. 
Next Using For loop 
<?php 
$con=mysql_connect("localhost","root",""); 
$db=mysql_select_db("yourdatabasename here" ,$con); 
$count=count($title); 
for($i=0;$i<$count;$i++){ 
mysql_query("INSERT INTO orders SET title='".$title[$i]."', quantity='".$quantity."'"); 
} 
?> 
+0

我没有太多帮助。 – Suspicius

相关问题