我使用runge-kutt方法创建了一个解决双体问题的程序。我遇到了这个问题:当我调用从表达式返回二维数组的ELEMENT的函数时,它必须给出二维数组的ELEMENT(对于术语造成的混淆),我得到以下消息:错误#6366:数组表达式的形状不符合
error #6366: The shapes of the array expressions do not conform.
[X1]
X1(DIM,i)=X1(DIM,i-1)+0.5D0*ABS(i/2)*H*K1(DIM,i-1,X1(DIM,i-1),X2(DIM,i-1),V1(DIM,i-1),V2(DIM,i-1),NDIM,ORD,2,maxnu)
我有这个函数的外部接口,它显然是编译器认为这是一个函数。
我必须澄清一些事情:
是的,这不是很Fortran语言,它的预处理器Trefor,用于在莫斯科大学的天文学家(我只是一个学生)。这种语言与fortran非常相似,但与C语言(例如,分号冒号)有点接近,许多学生对此进行了研究。 Runge-Kutta方法可简要地写为: 我们有初值问题
dy/dt=f(t,y), y(t0)=y0
y是未知向量,其中包含在我的情况12个组分(3个坐标和3倍的速度为每个体)
下一步是
y(n+1)=y(n)+1/6*h*(k1+2k2+2k3+k4), t(n+1)=t(n)+h
where
k1=f(tn,yn),
k2=f(tn+1/2h,yn+h/2*k1)
k3=f(tn+1/2h,yn+h/2*k2)
k4=f(tn+1/2h,yn+k3)
iee在我的代码X1,2和V1,2和K_1,2中应该是向量,因为它们中的每一个对于方法的每个'顺序'必须有3个空间分量和4个分量。 的完整代码:
FUNCTION K1(DIM,i,X1,X2,V1,V2,NDIM,ORD,nu,maxnu)RESULT (K_1);
integer,intent(in) :: i,DIM,nu;
real(8) :: K_1;
real(8) :: B1;
real(8) :: R;
real(8),intent(in) :: X1,X2,V1,V2;
COMMON/A/M1,M2,Fgauss,H;
integer,intent(in) :: NDIM,ORD,maxnu;
Dimension :: B1(NDIM, ORD);
Dimension :: X1(NDIM,ORD),X2(NDIM,ORD),V1(NDIM,ORD),V2(NDIM,ORD);
Dimension :: K_1(NDIM,ORD);
IF (nu>=2) THEN;
B1(DIM,i)=V1(DIM,i);
ELSE;
R=((X1(1,i)-X2(1,i))**2.D0+(X1(2,i)-X2(2,i))**2.D0+(X1(3,i)-X2(3,i))**2.D0)**0.5D0;
B1(DIM,i)=Fgauss*M2*(X2(DIM,i)-X1(DIM,i))/((R)**3.D0);
END IF;
K_1(DIM,i)=B1(DIM,i);
RETURN;
END FUNCTION K1;
FUNCTION K2(DIM,i,X1,X2,V1,V2,NDIM,ORD,nu,maxnu)RESULT (K_2);
integer,intent(in) :: i,DIM,nu;
real(8) :: K_2;
real(8) :: B2;
real(8) :: R;
real(8),intent(in) :: X1,X2,V1,V2;
COMMON/A/M1,M2,Fgauss,H;
integer,intent(in) :: NDIM,ORD,maxnu;
Dimension :: B2(NDIM,ORD);
Dimension :: X1(NDIM,ORD),X2(NDIM,ORD),V1(NDIM,ORD),V2(NDIM,ORD);
Dimension :: K_2(NDIM,ORD);
IF (nu>=2) THEN;
B2(DIM, i)=V2(DIM,i);
ELSE;
R=((X1(1,i)-X2(1,i))**2.D0+(X1(2,i)-X2(2,i))**2.D0+(X1(3,i)-X2(3,i))**2.D0)**0.5D0;
B2(DIM, i)=Fgauss*M1*(X2(DIM,i)-X1(DIM,i))/((R)**3.D0);
END IF;
K_2(DIM,i)=B2(DIM, i);
RETURN;
END FUNCTION K2;
PROGRAM RUNGEKUTT;
IMPLICIT NONE;
Character*80 STRING;
real(8) :: M1,M2,Fgauss,H;
real(8) :: R,X1,X2,V1,V2;
integer :: N,i,DIM,NDIM,maxnu,ORD;
integer :: nu;
PARAMETER(NDIM=3,ORD=4,maxnu=2);
Dimension :: X1(NDIM,ORD),X2(NDIM,ORD);
Dimension :: V1(NDIM,ORD),V2(NDIM,ORD);
INTERFACE;
FUNCTION K1(DIM,i,X1,X2,V1,V2,NDIM,ORD,nu,maxnu)RESULT (K_1);
integer,intent(in) :: i,DIM,nu;
real(8) :: K_1;
real(8) :: R;
real(8) :: B1;
real(8),intent(in) :: X1,X2,V1,V2;
COMMON/A/M1,M2,Fgauss,H;
integer,intent(in) :: NDIM,ORD,maxnu;
Dimension :: B1(NDIM, ORD);
Dimension :: X1(NDIM,ORD),X2(NDIM,ORD),V1(NDIM,ORD),V2(NDIM,ORD);
Dimension :: K_1(NDIM,ORD);
END FUNCTION K1;
FUNCTION K2(DIM,i,X1,X2,V1,V2,NDIM,ORD,nu,maxnu)RESULT (K_2);
integer,intent(in) :: i,DIM,nu;
real(8) :: K_2;
real(8) :: R;
real(8) :: B2;
real(8),intent(in) :: X1,X2,V1,V2;
COMMON/A/M1,M2,Fgauss,H;
integer,intent(in) :: NDIM,ORD,maxnu;
Dimension :: B2(NDIM,ORD);
Dimension :: X1(NDIM,ORD),X2(NDIM,ORD),V1(NDIM,ORD),V2(NDIM,ORD);
Dimension :: K_2(NDIM,ORD);
END FUNCTION K2;
END INTERFACE;
open(1,file='input.dat');
open(2,file='result.res');
open(3,file='mid.dat');
READ(1,'(A)') STRING;
READ(1,*) Fgauss,H;
READ(1,*) M1,M2;
READ(1,*) X1(1,1),X1(2,1),X1(3,1),V1(1,1),V1(2,1),V1(3,1);
READ(1,*) X2(1,1),X2(2,1),X2(3,1),V2(1,1),V2(2,1),V2(3,1);
WRITE(*,'(A)') STRING;
WRITE(3,'(A)') STRING;
WRITE(3,'(A,2G14.6)')' Fgauss,H:',Fgauss,H;
WRITE(3,'(A,2G14.6)')' M1,M2:',M1,M2;
WRITE(3,'(A,6G17.10)')' X1(1,1),X1(2,1),X1(3,1),V1(1,1),V1(2,1),V1(3,1):',X1(1,1),X1(2,1),X1(3,1),V1(1,1),V1(2,1),V1(3,1);
WRITE(3,'(A,6G17.10)')' X2(1,1),X2(2,1),X2(3,1),V2(1,1),V2(2,1),V2(3,1):',X2(1,1),X2(2,1),X2(3,1),V2(1,1),V2(2,1),V2(3,1);
R=((X1(1,1)-X2(1,1))**2.D0+(X1(2,1)-X2(2,1))**2.D0+(X1(3,1)-X2(3,1))**2.D0)**0.5D0;
N=0;
_WHILE N<=100 _DO;
i=2;
_WHILE i<=ORD _DO;
DIM=1;
_WHILE DIM<=NDIM _DO;
X1(DIM,i)=X1(DIM,i-1)+0.5D0*ABS(i/2)*H*K1(DIM,i-1,X1(DIM,i-1),X2(DIM,i-1),V1(DIM,i-1),V2(DIM,i-1),NDIM,ORD,2,maxnu);
X2(DIM,i)=X2(DIM,i-1)+0.5D0*H*ABS(i/2)*K2(DIM,i-1,X1(DIM,i-1),X2(DIM,i-1),V1(DIM,i-1),V2(DIM,i-1),NDIM,ORD,2,maxnu);
V1(DIM,i)=V1(DIM,i-1)+0.5D0*H*ABS(i/2)*K1(DIM,i-1,X1(DIM,i-1),X2(DIM,i-1),V1(DIM,i-1),V2(DIM,i-1),NDIM,ORD,1,maxnu);
V2(DIM,i)=V2(DIM,i-1)+0.5D0*H*ABS(i/2)*K2(DIM,i-1,X1(DIM,i-1),X2(DIM,i-1),V1(DIM,i-1),V2(DIM,i-1),NDIM,ORD,1,maxnu);
DIM=DIM+1;
_OD;
i=i+1;
_OD;
_WHILE DIM<=NDIM _DO;
X1(DIM,1)=X1(DIM,1)+1.D0/6.D0*H*(K1(DIM,1,X1(DIM,1),X2(DIM,1),V1(DIM,1),V2(DIM,1),NDIM,ORD,2,maxnu)+2.D0*K1(DIM,2,X1(DIM,2),X2(DIM,2),V1(DIM,2),V2(DIM,2),NDIM,ORD,2,maxnu)+2.D0*K1(DIM,3,X1(DIM,3),X2(DIM,3),V1(DIM,3),V2(DIM,3),NDIM,ORD,2,maxnu)+K1(DIM,4,X1(DIM,4),X2(DIM,4),V1(DIM,4),V2(DIM,4),NDIM,ORD,2,maxnu));
X2(DIM,1)=X2(DIM,1)+1.D0/6.D0*H*(K2(DIM,1,X1(DIM,1),X2(DIM,1),V1(DIM,1),V2(DIM,1),NDIM,ORD,2,maxnu)+2.D0*K2(DIM,2,X1(DIM,2),X2(DIM,2),V1(DIM,2),V2(DIM,2),NDIM,ORD,2,maxnu)+2.D0*K2(DIM,3,X1(DIM,3),X2(DIM,3),V1(DIM,3),V2(DIM,3),NDIM,ORD,2,maxnu)+K2(DIM,4,X1(DIM,4),X2(DIM,4),V1(DIM,4),V2(DIM,4),NDIM,ORD,2,maxnu));
V1(DIM,1)=V1(DIM,1)+1.D0/6.D0*H*(K1(DIM,1,X1(DIM,1),X2(DIM,1),V1(DIM,1),V2(DIM,1),NDIM,ORD,1,maxnu)+2.D0*K1(DIM,2,X1(DIM,2),X2(DIM,2),V1(DIM,2),V2(DIM,2),NDIM,ORD,2,maxnu)+2.D0*K2(DIM,3,X1(DIM,3),X2(DIM,3),V1(DIM,3),V2(DIM,3),NDIM,ORD,2,maxnu)+K2(DIM,4,X1(DIM,4),X2(DIM,4),V1(DIM,4),V2(DIM,4),NDIM,ORD,2,maxnu));
V2(DIM,1)=V2(DIM,1)+1.D0/6.D0*H*(K2(DIM,1,X1(DIM,1),X2(DIM,1),V1(DIM,1),V2(DIM,1),NDIM,ORD,1,maxnu)+2.D0*K2(DIM,2,X1(DIM,2),X2(DIM,2),V1(DIM,2),V2(DIM,2),NDIM,ORD,1,maxnu)+2.D0*K2(DIM,3,X1(DIM,3),X2(DIM,3),V1(DIM,3),V2(DIM,3),NDIM,ORD,1,maxnu)+K2(DIM,4,X1(DIM,4),X2(DIM,4),V1(DIM,4),V2(DIM,4),NDIM,ORD,1,maxnu));
_OD;
R=((X1(1,5)-X2(1,5))**2.D0+(X1(2,5)-X2(2,5))**2.D0+(X1(3,5)-X2(3,5))**2.D0)**0.5D0;
N=N+1;
write(2,'(A,1i5,6g12.5)')' N,X1(1,1),X1(2,1),X1(3,1),X2(1,1),X2(2,1),X2(3,1):',N,X1(1,1),X1(2,1),X1(3,1),X2(1,1),X2(2,1),X2(1,1),X2(2,1),X2(3,1);
_OD;
END PROGRAM RUNGEKUTT;
请帮助,看来,我不明白,在使用功能的东西!
您收到的错误消息来自英特尔Fortran编译器,因此在某些时候必须有真正的Fortran代码进行编译。这是什么?预处理器的输出是什么?如果我试图从Trefor到Fortran进行明显的翻译,我下面的答案保持不变。您将函数K1的返回值声明为一个数组,但是您将其用于不允许为数组的上下文中(因为您正在分配给一个标量)。 –