GDB堆栈输出没有显示完整的十六进制地址？

Question

我GDB输出堆栈看起来像这样

0xffffd688:  0x98 0xd6 0xff 0xff 0x75 0x84 0x04 0x08 

我想它看起来更像这

0xbffff3b0: 0xbffff620 0xbffff3c9 0×00000006 0xbffff3d8 

有一个选项？我在这里错过了一些微不足道的东西吗？

Answer 1

你确实想(gdb) x/4xw $sp：

(gdb) help x 
Examine memory: x/FMT ADDRESS. 
ADDRESS is an expression for the memory address to examine. 
FMT is a repeat count followed by a format letter and a size letter. 
Format letters are o(octal), x(hex), d(decimal), u(unsigned decimal), 
    t(binary), f(float), a(address), i(instruction), c(char) and s(string). 
Size letters are b(byte), h(halfword), w(word), g(giant, 8 bytes). 
The specified number of objects of the specified size are printed 
according to the format. 

在这种情况下，重复计数是4，将格式信是x（十六进制）和大小字母是w（字，4字节）。