如何将JSONObject转换为字符串数组或ArrayList <String> android

Question

我将获取JSONObject的值并将其放入String Array或ArrayList中。问题是我有一个JSONObject而不是JSONArray，并且我无法更改Webservice。 这是我的JSONObject：

{ “THR”： “تهران”， “MHD”： “مشهد”， “KIH”： “کیش”， “IFN”： “اصفهان”， “SYZ” ： “شیراز”， “TBZ”： “تبریز”， “ABD”： “آبادان”}

这是我的代码：

ProgressBar progressbar = (ProgressBar) findViewById(R.id.progressbar); 
    RequestQueue queue = Volley.newRequestQueue(getApplicationContext()); 

    progressbar.setVisibility(View.VISIBLE); 
    StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() { 
     @Override 
     public void onResponse(String response) { 
      Toast.makeText(getApplicationContext(), "Response", Toast.LENGTH_SHORT).show(); 
      progressbar.setVisibility(View.GONE); 

      try { 
       JSONArray array = new JSONArray(response); 
       Toast.makeText(getApplicationContext(), "Try", Toast.LENGTH_LONG).show(); 
      } catch (JSONException e) { 
       e.printStackTrace(); 
       Toast.makeText(getApplicationContext(), "Catch", Toast.LENGTH_LONG).show(); 
      } 

     } 
    }, new Response.ErrorListener() { 
     @Override 
     public void onErrorResponse(VolleyError error) { 
      Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_SHORT).show(); 
      progressbar.setVisibility(View.GONE); 
     } 
    }); 

    queue.add(stringRequest); 

当我调试我的代码，它会赶上！ 不管怎样，它都不会去TRY！

我想是这样的：

String[] strArray = {"تهران","مشهد","کیش","اصفهان","شیراز","تبریز","آبادان"}; 

我怎样才能得到它呢？

Answer 1

添加代码的修改

ProgressBar progressbar = (ProgressBar) findViewById(R.id.progressbar); 
    RequestQueue queue = Volley.newRequestQueue(getApplicationContext()); 
    ArrayList<String> answersStringArray= new ArrayList<String>(); // define string array 

progressbar.setVisibility(View.VISIBLE); 
    StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() { 
     @Override 
     public void onResponse(String response) { 
      Toast.makeText(getApplicationContext(), "Response", Toast.LENGTH_SHORT).show(); 
      progressbar.setVisibility(View.GONE); 

      try { 
       JJSONObject jsonObject = new JSONObject(response); //cast responce to jsonObject 
       Iterator<?> keys = jsonObject.keys(); // get the keys of the jsonObject 
       while(keys.hasNext()) {//iterrate over them 
        String key = (String)keys.next(); 
        answersStringArray.add(jsonObject.optString(key));}// add the string to our array of stings 


      } catch (JSONException e) { 
       e.printStackTrace(); 
       Toast.makeText(getApplicationContext(), "Catch", Toast.LENGTH_LONG).show(); 
      } 

     } 
    }, new Response.ErrorListener() { 
     @Override 
     public void onErrorResponse(VolleyError error) { 
      Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_SHORT).show(); 
      progressbar.setVisibility(View.GONE); 
     } 
    }); 

    queue.add(stringRequest); 

Answer 2

public static void main(String[] args) { 
//building your jsonObject(took only the 1st four ;P) 
     JSONObject objJsonObject = new JSONObject(); 
     objJsonObject.put("THR", "تهران"); 
     objJsonObject.put("MHD", "مشهد"); 
     objJsonObject.put("KIH", "کیش"); 
     objJsonObject.put("IFN", "اصفهان"); 
     String [] strArray= new String[objJsonObject.length()]; 
     int i = 0; 
//adding your required data into a array 
     for (String key: objJsonObject.keySet()) { 
      strArray[i] = objJsonObject.getString(key); 
      i++; 
     } 
//printing your data 
     for (int j = 0; j < strArray.length; j++) { 
      System.out.println(strArray[j]); 
     } 
} 

希望这有助于....