SQL删除所有行的时间戳比（现在 - x天）要早，除了保留最近的n条记录

Question

如果我有下表，我需要删除所有比（现在 - x天）更早的记录，但不是在最近的n个记录中。

具体的例子：用户不能在90天内和重复使用的密码可能不会再使用过去的10个密码。如果我每90天更换一次密码，我仍然无法重复使用密码进行10次更改。

CREATE TABLE PASSWORD_HISTORY (
      ID BIGINT NOT NULL AUTO_INCREMENT, 
      USER_NAME VARCHAR(255) NOT NULL, 
      PASSWORD VARCHAR(255) NOT NULL, 
      SALT VARCHAR(255), 
      CREATED_TIMESTAMP BIGINT NOT NULL, 
      UPDATED_TIMESTAMP BIGINT NOT NULL, 
      TENANT_ID INTEGER DEFAULT -1234, 
      PRIMARY KEY (ID) 
)ENGINE INNODB; 

Answer 1

-- drop table password_history; 
create table password_history 
(
id bigint null auto_increment primary key, 
user_name varchar(255) not null, 
created_timestamp bigint not null 
); 

-- delete from password_history where id>0; -- safe mode sometimes barfs 
insert password_history (user_name,created_timestamp) values ('fred',100); 
insert password_history (user_name,created_timestamp) values ('fred',200); 
insert password_history (user_name,created_timestamp) values ('fred',300); 
insert password_history (user_name,created_timestamp) values ('fred',400); 
insert password_history (user_name,created_timestamp) values ('fred',401); 
insert password_history (user_name,created_timestamp) values ('fred',402); 
insert password_history (user_name,created_timestamp) values ('fred',403); 
insert password_history (user_name,created_timestamp) values ('fred',404); 
insert password_history (user_name,created_timestamp) values ('fred',405); 
insert password_history (user_name,created_timestamp) values ('fred',406); 
insert password_history (user_name,created_timestamp) values ('fred',407); 
insert password_history (user_name,created_timestamp) values ('fred',500); 
insert password_history (user_name,created_timestamp) values ('fred',555); 

insert password_history (user_name,created_timestamp) values ('fred',unix_timestamp(now())); 
insert password_history (user_name,created_timestamp) values ('stan',unix_timestamp(now())); 

alter table password_history add deleteMe int; 

select * from password_history; 

-- variables n and d 
-- n=10, users last 10 records 
-- d=90, last 90 days 
-- rows where password created more than 90 days ago (replace 90 below as desired) 
select * from password_history 
where unix_timestamp(now()) - created_timestamp>(60*60*24*90) 
order by id desc 

-- update password_history set deleteMe=1 where id>0; -- safe mode sometimes barfs 

-- update password_history set deleteMe=null where id>0; -- safe mode sometimes barfs 

update password_history 
join 
(
select ph.id,ph.user_name,ph.created_timestamp 
from password_history ph 
join 
(
select ph.id,ph.user_name,ph.created_timestamp 
from password_history ph 
join 
(
select user_name,max(id),max(created_timestamp),count(*) as theCount 
from password_history xx 
group by user_name 
having theCount>10 
) inR2 
on ph.user_name=inR2.user_name 
order by ph.user_name,ph.created_timestamp desc 
limit 10 
) inR1 
on ph.id=inR1.id 
) bigThing 
on password_history.id=bigThing.id 
set deleteMe='1' 
where password_history.id>0 -- this gets rid of the safe mode barfing 

update password_history 
join 
(
select user_name from password_history p2 where p2.deleteMe=1 
) phMany 
on password_history.user_name=phMany.user_name 
set deleteMe=2 
where password_history.deleteMe is null 

-- select * from password_history order by user_name,created_timestamp desc; 

-- look at the ones with deleteMe=2 

Answer 2

DELETE 
FROM PASSWORD_HISTORY 
Where PASSWORD_HISTORY.ID Not IN 

(
    SELECT ID FROM(SELECT pass1.[USER_NAME], Count(*) num, pass1.ID 
    FROM Password_History pass1 JOIN Password_History pass2 
     ON pass1.[USER_NAME] = pass2.[USER_NAME] AND pass1.ID <= pass2.ID 
    Group BY pass1.[USER_NAME], pass1.ID 
    Having Count(*) <= 10 

) a 

) 
AND CREATED_TIMESTAMP <= Convert(int, DATEADD(day, -90, GetDate())) 

这如果这些行属于一个用户名超过10个记录和那些行有超过90天前Created_TimeStamp只会删除具有最低ID的行。当然，你应该用SELECT *来代替DELETE来确保它给你你想要的东西。此外，我会运行一个Begin Transaction;，并准备好Rollback Transaction;，如果它在删除时变酸。

Answer 3

如果我理解正确，您想要删除最近记录超过90天并且其密码不在最近90天内的记录。我不知道为什么你真的需要删除这些。当你查询数据时，你可以施加这些规则，而不是数据本身。然后，如果你喜欢，你可以轻松地将规则更改为120天。

在任何情况下，如果仅为每位用户列举密码，这将会简单得多。但他们不是，MySQL不支持row_number()。这表明使用变量来枚举结果。由于MySQL的规则，这需要子查询和delete中的join。剩下的只是基本条件逻辑：

delete ph 
    from password_history ph join 
     (select ph2.*, 
       (@rn := if(@u = user_name, @rn + 1, 
          if(@u := user_name, 1, 1) 
          ) 
       ) as seqnum 
      from password_history ph2 cross join 
       (select @rn := 0, @u := '') params 
      order by user_name, created_timestamp desc 
     ) ph2 
     on ph2.id = ph.id 
    where ph2.seqnum > 10 and 
      ph.created_timestamp <= date_sub(curdate(), interval 90 day)