SQL Server XML替换属性中的值

Question

我想要替换XML中属性的值。该属性在xml中多次出现。我怎么能代替这些一次性

我的XML lools一些什么样的如下：

<Example> 
    <A> 
    <B Type = "x">qqq</B> 
    <B Type = "x">www</B> 
    </A> 
    <C> 
    <D Type = "x">aaa</D> 
    <D Type = "x">uuu</D> 
    </C> 
</Example> 

我想Ÿ

Answer 1

全部更换x你不能代替一次性使用replace value of (XML DML)。你必须循环做。

declare @xml xml = ' 
<Example> 
    <A> 
    <B Type = "x">qqq</B> 
    <B Type = "x">www</B> 
    </A> 
    <C> 
    <D Type = "x">aaa</D> 
    <D Type = "x">uuu</D> 
    </C> 
</Example> 
' 

while (select @xml.exist('//*[@Type = "x"]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type = "x"]/@Type)[1] with "y"') 
end 

select @xml 

结果：

<Example> 
    <A> 
    <B Type="y">qqq</B> 
    <B Type="y">www</B> 
    </A> 
    <C> 
    <D Type="y">aaa</D> 
    <D Type="y">uuu</D> 
    </C> 
</Example> 

更新

替换值X和Z与Y：

while (select @xml.exist('//*[@Type = ("x","z")]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type = ("x","z")]/@Type)[1] with "y"') 
end 

，其中y替换所有值：

while (select @xml.exist('//*[@Type != "y"]')) = 1 
begin 
    set @xml.modify('replace value of (//*[@Type != "y"]/@Type)[1] with "y"') 
end