2010-03-21 80 views
2

我想写使用AudioFileWriteBytes()原始音频字节的文件。下面是我在做什么:AudioFileWriteBytes失败,错误代码-40

void writeSingleChannelRingBufferDataToFileAsSInt16(AudioFileID audioFileID, AudioConverterRef audioConverter, ringBuffer *rb, SInt16 *holdingBuffer) { 
// First, figure out which bits of audio we'll be 
// writing to file from the ring buffer 

    UInt32 lastFreshSample = rb->lastWrittenIndex; 
    OSStatus status; 
    int numSamplesToWrite; 
    UInt32 numBytesToWrite; 


    if (lastFreshSample < rb->lastReadIndex) { 
     numSamplesToWrite = kNumPointsInWave + lastFreshSample - rb->lastReadIndex - 1; 
    } 
    else { 
     numSamplesToWrite = lastFreshSample - rb->lastReadIndex; 
    } 
    numBytesToWrite = numSamplesToWrite*sizeof(SInt16); 

然后我们的音频数据(存储为花车)复制到将直接写入文件保持缓冲(SInt16)。复制看起来很时髦,因为它来自环形缓冲区。

UInt32 buffLen = rb->sizeOfBuffer - 1; 
    for (int i=0; i < numSamplesToWrite; ++i) { 
     holdingBuffer[i] = rb->data[(i + rb->lastReadIndex) & buffLen]; 
    } 

好的,现在我们尝试从SInt16缓冲区“holdingBuffer”写入音频到音频文件。该的NSLog会吐出一个错误-40,但还声称,它的写入字节。没有数据写入文件。

status = AudioFileWriteBytes(audioFileID, NO, 0, &numBytesToWrite, &holdingBuffer);  
    rb->lastReadIndex = lastFreshSample; 

    NSLog(@"Error = %d, wrote %d bytes", status, numBytesToWrite); 

    return; 

什么是这个错误-40?顺便说一句,一切如果我写,直接从ringBuffer到文件工作正常。当然,这听起来像垃圾,因为我写的花车,没有SInt16s,但AudioFileWriteBytes不抱怨。

回答

2

的关键是输入数据的字节序明确更改为大端。我所要做的就是包装CFSwapInt16HostToBig在我的数据获取:

float audioVal = rb->data[(i + rb->lastReadIndex) & buffLen]; 
holdingBuffer[i] = CFSwapInt16HostToBig((SInt16) audioVal); 
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