根据值对列重新排序

Question

有什么方法可以根据值对表（或查询）中的列重新排序。

例如，在每一行上，FacName应该是第一个，NPI - 第2个，TIN - 第3个和地址 - 第4个。

谢谢！

Answer 1

要移动列之间的数据的事实强烈地暗示出底层的数据模型被打破，需要进行标准化。修复数据模型比为系统增加另一层复杂性要合适得多。

话虽这么说，你应该能够做到像

SELECT (CASE WHEN column1 LIKE 'FacilityName%' THEN column1 
      WHEN column2 LIKE 'FacilityName%' THEN column2 
      WHEN column3 LIKE 'FacilityName%' THEN column3 
      WHEN column4 LIKE 'FacilityName%' THEN column4 
      ELSE null 
     END) column1, 
     (CASE WHEN column1 LIKE 'NPI%' THEN column1 
      WHEN column2 LIKE 'NPI%' THEN column2 
      WHEN column3 LIKE 'NPI%' THEN column3 
      WHEN column4 LIKE 'NPI%' THEN column4 
      ELSE null 
     END) column2, 
     (CASE WHEN column1 LIKE 'TIN%' THEN column1 
      WHEN column2 LIKE 'TIN%' THEN column2 
      WHEN column3 LIKE 'TIN%' THEN column3 
      WHEN column4 LIKE 'TIN%' THEN column4 
      ELSE null 
     END) column3, 
     (CASE WHEN column1 LIKE 'Address%' THEN column1 
      WHEN column2 LIKE 'Address%' THEN column2 
      WHEN column3 LIKE 'Address%' THEN column3 
      WHEN column4 LIKE 'Address%' THEN column4 
      ELSE null 
     END) column4 
    FROM(<<your query>>) 

Answer 2

select col1, col2, col3, col4 from (
    select * from (
    select 
     n, str, row_number() over (partition by n order by 
     decode(substr(str,1,3),'Fac',1,'NPI',2,'TIN',3,'Add',4)) cn 
    from (
     select * from (select t.*, rownum n from t) 
     unpivot (str for cn in (col1 as 0, col2 as 0, col3 as 0, col4 as 0)) 
    ) 
) 
    pivot (min(str) for cn in (1 as col1, 2 as col2, 3 as col3, 4 as col4)) 
) 
order by n 

fiddle