我想知道如果我正在做一个正确的表格写入,它似乎失败。MySQL表格插入
while($n != 1)
{
$randstring = "live_".RandomString();
echo "<br>".$username."<br>";
echo $randstring."<br>";
$idcheck = mysql_query("SELECT * FROM streamer_ids WHERE streamer_id='".$randstring."'"); //check for matching random strings
if (!(mysql_num_rows($idcheck)>0))
{
$n=1; //It has found a random string that does not match.
}
}
//if it has reached this far, it has a unique id. Now that id is being written to the database.
$temp = mysql_query("INSERT INTO streamer_ids (username,streamer_id,premium) VALUES(".$username.",".$randstring.","0")");
$temp->closeCursor();
请注意,最后一部分被严重屠杀,这是我需要帮助。
1.你可以发布你正在得到的错误2.强制性SQL注入警告 - 使用参数3.你对匹配随机字符串的唯一性检查似乎是多余的 - 你试图用它来实现什么? – InSane 2010-12-09 04:09:09
它需要是完全独特的,如果匹配的话它会继续重新生成随机字符串。 – 2010-12-09 04:19:48