猜数字游戏java

Question

我正在写一个java代码，要求用户猜测计算机的随机数，我很好，但是，我想要做的是有一个消息对应的猜测数拿走了用户。

例如，如果用户猜测1中的随机数，尝试输出“优秀！”。如果用户猜到2-4的答案尝试“好工作”等。

我想我还没有尝试过任何东西，因为我不知道在哪里粘住代码？
我知道它必须如果猜== = 1然后做这个如果代码> 1 < = 3然后这样做等等..但在我的代码？它应该在嵌套if的while循环中吗？

这是我更新的代码，它运行并编译我创建它所需的确切方式。感谢所有的帮助！

public static void main(String[] args) { 
     Random rand = new Random(); 
     int compNum = rand.nextInt(100); 
     int count = 0; 
     Scanner keyboard = new Scanner(System.in); 
     int userGuess; 
     boolean win = false;   
     while (win == false){ 
      System.out.print("Enter a guess between 1 and 100: "); 
      userGuess = keyboard.nextInt(); 
      count++; 
      if(userGuess < 1 || userGuess > 100){ 
       System.out.println("Your guess is out of range. Pick a number between 1 and 100."); 
       System.out.println(); 
      } 
      else if (userGuess == compNum){ 
       win = true; 
       System.out.println("Congratulations! Your answer was correct! "); 
      }  
      else if (userGuess < compNum){ 
       System.out.println("Your guess was too low. Try again. "); 
       System.out.println(); 
      } 
      else if (userGuess > compNum){ 
       System.out.println("Your guess was too high. Try again. "); 
       System.out.println(); 
      } 

     } 
     if(count == 1){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("That was lucky!"); 
     } 
     else if (count > 1 && count <= 4){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("That was amazing!"); 
     } 
     else if (count > 4 && count <= 6){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("That was good."); 
     } 
     else if (count > 6 && count <= 7){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("That was OK."); 
     }    
     else if (count > 7 && count <= 9){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("That was not very good."); 
     } 
     else if (count > 10){ 
      System.out.println(); 
      System.out.println("I had chosen " + compNum + " as the target number."); 
      System.out.println("You guessed it in " + count + " tries."); 
      System.out.println("This just isn't your game."); 

     } 
    } 
     } 

Answer 1

保持一个计数的int i;，每个用户猜测时间错误（如果没有用户得到正确的答案，做i++然后，有这样的事，你回应TI正确的答案如下：

if(i == 0) System.out.println("Perfect!"); //Got it the first time 
else if(i == 1) System.out.println("Nice!"); //Got it on the second try 
else if(i <= 4) System.out.println("Good Job!"); //Got it between the second and fifth time 
else if(i <= 8) System.out.println("Okay!"); //Got it between 6th and 9th time 
else System.out.println("Hmmm... Try to do better next time!"); //took more than 10 times to get it right 

Answer 2

你可以指望的迭代。喜欢的东西。

boolean notCorrect = true; 
int guesses = 0; 
while(notCorrect){ 
    //Code for checking user input. 
    //break out if true 
    guesses++; 
} 

对不起，这倒退了。

别处

if(guesses < 2) { 
    // display message 
} 
// include other if's to determine which message to display. 

你可以把if语句来决定在显示哪一条消息如果检查的猜测是否正确。但是把它拉出循环。这样，如果用户实际猜测正确，那么您只能运行该代码。

if (userGuess == compNum){ 
    win = true; 
    System.out.println("Congratulations! Your answer was correct! "); 
    // put message decision here... 
}