将Excel Formual转换为SQL

我在Excel中有一个计算两个日期之间有多少星期日的公式，但我想在SQL中执行相同的操作，但无法弄清楚如何执行此操作。你能帮我吗？将Excel Formual转换为SQL

=SUM(INT((WEEKDAY(A1-8,1)+B1-A1)/7)) 

Declare @From as Datetime 
Declare @To as Datetime 

Set @From = '7 Jan 2013' 
Set @To = '18 Mar 2013' 

SELECT SUM(WEEKDATE(@From-8,1)+ @[email protected])/7)) AS No_Of_Sundays 
FROM TIME

感谢

韦恩

来源

2013-02-28 wafw1971

试试这个：

SELECT SUM((CASE WHEN DATEPART(dw, @From) = 7 THEN 1 ELSE 0 END) + DATEDIFF(dd, @From, @To)/7) AS No_Of_Sundays

正如你看到的，这取决于本地化 - >俄罗斯星期日是一天＃7，所以我们做一个检查，如果第一天是星期日

下面是另一种解决方案：

Declare @From as Datetime 
Declare @To as Datetime 
Declare @sundays as INT 

Set @From = '1/02/2013' 
Set @To = '28/02/2013' 
Set @sundays = 0 

WHILE (@From <= @To) 
BEGIN 
    SET @sundays = @sundays + (CASE WHEN DATEPART(dw, @From) = 7 THEN 1 ELSE 0 END) 
    SET @From = DATEADD(dd, 1, @From) 
END 

SELECT @sundays

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2013-02-28 09:40:05 Sergio

塞尔吉奥嗨，什么是错的，因为它不包括所有的星期天，例如在二月份有4个，但SQL计数3 – wafw1971 2013-02-28 09:52:26

编辑 - 红粉另一种解决方案that'l工作just perfect – Sergio 2013-02-28 10:04:49

我收到此错误消息：消息242，级别16，状态3，行6 将varchar数据类型转换为日期时间数据类型导致超出范围的值。 – wafw1971 2013-02-28 10:09:38

如果您使用sql-server 2005或更高版本，这是一种使用CTE的方法。这里是一个demo

declare @From date = '20130107' --'7 Jan 2013' 
declare @To date = '20130318' --'18 Mar 2013' 

;with CTE as (
    select 0 number , datename(weekday, @from) dName 
    union all 
    select number+1, datename(weekday,dateadd(day,number+1,@from)) dName 
    from CTE 
    where dateadd(day, number + 1,@from) <= @to and 
     datename(weekday,dateadd(day,number,@from)) <> 'sunday' 
) 

select top(1) (datediff(day,@from,@to) - number)/7 + 
       case when number = 0 and dname <> 'sunday' then 0 else 1 end 
       sundays 
from CTE 
order by number desc

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2013-02-28 10:36:42 Kaf

将Excel Formual转换为SQL

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