我想将文件上传到远程设备。 如果我看到了Wireshark的连接我得到这个如何更改内容类型Python
POST /saveRestore.htm.cgi HTTP/1.1
Host: 10.128.115.214
User-Agent: Mozilla/5.0 (X11; Ubuntu; Linux i686; rv:15.0) Gecko/20100101 Firefox/15.0.1
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: de-de,de;q=0.8,en-us;q=0.5,en;q=0.3
Accept-Encoding: gzip, deflate
Connection: keep-alive
Referer: http://10.128.115.214/saveRestore.htm
Cache-Control: max-age=0
Content-Type: multipart/form-data; boundary=---------------------------961265085509552220604142744
Content-Length: 10708
-----------------------------961265085509552220604142744
Content-Disposition: form-data; name="restore"; filename="config(2).cfg"
Content-Type: application/octet-stream
现在这说的是,浏览器只接受text/html的,是application/xhtml + xml的,应用/ XML; Q = 0.9,/; q = 0.8
如果我上传的文件与我的脚本,它说
--0a7125aebb8845ba8ab9aa21306b01f6
Content-Disposition: form-data; name="restore"; filename="Config.cfg"
Content-Type: text/plain; charset=utf-8
所以这是一个错误的文件类型..
那么如何更改文件的内容类型?
我的代码看起来到目前为止如下:
#!/usr/bin/python
import httplib
import urllib2
from poster.encode import multipart_encode
import poster
from poster.streaminghttp import register_openers
register_openers()
params = {'restore': open("Config.cfg", "rb"), 'upload': 'PC ==>; Unit'}
datagen, headers = multipart_encode(params)
request = urllib2.Request('http://10.128.115.214/saveRestore.htm.cgi', datagen, headers)
u = urllib2.urlopen(request)
print u.read()
可能重复(海报)](http://stackoverflow.com/questions/12669274/wrong-content-type-when-transfering-file-with-python-poster) –
这是完全不清楚。什么是服务器和什么是客户端,你在哪里设置内容类型/处置? – njzk2
服务器是10.128.115.214 saveRestore.htm.cgi是一个用于上传和恢复文件的Web界面......并且我尝试使用脚本而不是Web界面执行该操作......并且如果我执行uplaod与网络接口...和文件的内容类型是错误的,当我这样做与脚本 – VanDeath