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我已经在python中建立了一个数独求解器回溯算法,只是为了找出它不起作用。我看了一下互联网上的例子,发现与我的情况相比,他们所做的只有一件事情不同。我相应地更改了我的代码,现在我的程序正常工作。数独求解器需要Python算法说明
这里是工作代码:
sudoku = []
next_empty_pos = [0,0]
# Check if the number is already used in the given row
def valid_in_row(number,row):
for i in range(9):
if(sudoku[row][i] == number):
return False
return True
# Check if the number is already used in the given column
def valid_in_col(number,col):
for i in range(9):
if(sudoku[i][col] == number):
return False;
return True;
# Check if the number is already used in the given 3x3 box
def valid_in_box(number,row,col):
# Find where 3x3 row and col starts
col_start = col-col%3
row_start = row-row%3
# Loop through the 3 columns and 3 rows
for i in range(3):
for z in range(3):
if(sudoku[i+row_start][z+col_start] == number):
return False
return True
# Check if the position is valid for the given number by checking all three conditions above
def position_valid(number,row,col):
return valid_in_row(number,row) and valid_in_col(number,col) and valid_in_box(number,row,col)
# Find if there are any empty cells left and assign the next empty cell
def empty_position_exists():
for row in range(9):
for col in range(9):
if(sudoku[row][col] == 0):
global next_empty_pos
next_empty_pos = [row,col]
return True
return False
# Solve the sudoku
def solve_sudoku():
# If there are no more empty cells, we are finished
if(not empty_position_exists()):
return True
row=next_empty_pos[0]
col=next_empty_pos[1]
# Try numbers from 1
for posssible_number in range(1,10):
if(position_valid(posssible_number,row,col)):
sudoku[row][col] = posssible_number
# If the next function call evalutes to true, then this should be true as well
if(solve_sudoku()):
return True
# If the above did not work then, set the number back to 0 (unassgined)
sudoku[row][col] = 0
# Return false if none of the numbers were good
return False
我原来的代码不同的是,我经过next_empty_pos[0]
和next_empty_pos[1]
直接在我solve_sudoku
功能,而不是声明为外部独立row
和col
变量for循环。
我的功能看起来像这样:
# Solve the sudoku
def solve_sudoku():
# If there are no more empty cells, we are finished
if(not empty_position_exists()):
return True
# Try numbers from 1
for posssible_number in range(1,10):
if(position_valid(posssible_number,next_empty_pos[0],next_empty_pos[1])):
sudoku[next_empty_pos[0]][next_empty_pos[1]] = posssible_number
# If the next function call evalutes to true, then this should be true as well
if(solve_sudoku()):
return True
# If the above did not work then, set the number back to 0 (unassgined)
sudoku[next_empty_pos[0]][next_empty_pos[1]] = 0
# Return false if none of the numbers were good
return False
有人能解释为什么我的版本是不工作?
在此先感谢。
是的,这是有道理的。谢谢! –