我目前正在使用Plistlib模块来读取Plist文件,但是当它涉及到二进制Plist文件时,我目前遇到了问题。用Python读取二进制Plist文件
我想读取数据到一个字符串,以便以后分析/打印等。我想知道如果他们无论如何读取二进制Plist文件中不使用plutil函数并将二进制文件转换为XML?
谢谢您的帮助和时间提前。
我目前正在使用Plistlib模块来读取Plist文件,但是当它涉及到二进制Plist文件时,我目前遇到了问题。用Python读取二进制Plist文件
我想读取数据到一个字符串,以便以后分析/打印等。我想知道如果他们无论如何读取二进制Plist文件中不使用plutil函数并将二进制文件转换为XML?
谢谢您的帮助和时间提前。
您可以使用工具plutil(来自http://www.libimobiledevice.org/的libplist)将二进制文件转换为xml plist文件(反之亦然)。
虽然你没有指定plutil
,因为它预装Mac上用它工作的解决方案可能是有用的人:
import json
from subprocess import Popen, PIPE
def plist_to_dictionary(filename):
"Pipe the binary plist through plutil and parse the JSON output"
with open(filename, "rb") as f:
content = f.read()
args = ["plutil", "-convert", "json", "-o", "-", "--", "-"]
p = Popen(args, stdin=PIPE, stdout=PIPE)
out, err = p.communicate(content)
return json.loads(out)
print plist_to_dictionary(path_to_plist_file)
如果给这个函数提供了足够大的输入,它会停留在p.stdin.write(内容)上。请阅读文档。 – zhangyoufu 2016-03-03 04:30:01
@张有福正确,谢谢 – orip 2016-03-03 09:52:08
Biplist https://github.com/wooster/biplist可通过简单的安装或点子。
你可以看看CFBinaryPList.c源文件,看看它是如何在C.
基于文件的实施,它的格式是这样:
HEADER
magic number ("bplist")
file format version (currently "0?")
OBJECT TABLE
variable-sized objects
Object Formats (marker byte followed by additional info in some cases)
null 0000 0000 // null object [v"1?"+ only]
bool 0000 1000 // false
bool 0000 1001 // true
url 0000 1100 string // URL with no base URL, recursive encoding of URL string [v"1?"+ only]
url 0000 1101 base string // URL with base URL, recursive encoding of base URL, then recursive encoding of URL string [v"1?"+ only]
uuid 0000 1110 // 16-byte UUID [v"1?"+ only]
fill 0000 1111 // fill byte
int 0001 0nnn ... // # of bytes is 2^nnn, big-endian bytes
real 0010 0nnn ... // # of bytes is 2^nnn, big-endian bytes
date 0011 0011 ... // 8 byte float follows, big-endian bytes
data 0100 nnnn [int] ... // nnnn is number of bytes unless 1111 then int count follows, followed by bytes
string 0101 nnnn [int] ... // ASCII string, nnnn is # of chars, else 1111 then int count, then bytes
string 0110 nnnn [int] ... // Unicode string, nnnn is # of chars, else 1111 then int count, then big-endian 2-byte uint16_t
string 0111 nnnn [int] ... // UTF8 string, nnnn is # of chars, else 1111 then int count, then bytes [v"1?"+ only]
uid 1000 nnnn ... // nnnn+1 is # of bytes
1001 xxxx // unused
array 1010 nnnn [int] objref* // nnnn is count, unless '1111', then int count follows
ordset 1011 nnnn [int] objref* // nnnn is count, unless '1111', then int count follows [v"1?"+ only]
set 1100 nnnn [int] objref* // nnnn is count, unless '1111', then int count follows [v"1?"+ only]
dict 1101 nnnn [int] keyref* objref* // nnnn is count, unless '1111', then int count follows
1110 xxxx // unused
1111 xxxx // unused
OFFSET TABLE
list of ints, byte size of which is given in trailer
-- these are the byte offsets into the file
-- number of these is in the trailer
TRAILER
byte size of offset ints in offset table
byte size of object refs in arrays and dicts
number of offsets in offset table (also is number of objects)
element # in offset table which is top level object
offset table offset
[二进制的plist Python模块]的可能的复制(http://stackoverflow.com/q/3725268/222914) – 2012-01-13 20:13:38
谢谢Janne,我看过这篇文章,但我希望如果有人知道如何在不安装单独模块的情况下执行上述操作并仅使用预安装的模块Python提供。 – 2012-01-14 09:29:53
名为plistlib的默认模块不处理二进制plist文件。你最好选择“biplist”或其他第三模块。 – 2012-06-18 07:46:16