结果cout <<“Hello”+ 1 << endl; （C++）

Question

你能帮我解释下面的代码的结果吗？

cout<< "Hello" + 1<< endl; 

为什么结果出来为 “ELLO”，我知道打印出Hello1那么我应该使用： COUT < < “你好” < < ENDL; 但谁能帮我解释一下上面代码的顺序： 非常感谢。

Answer 1

你的例子是大致相当于此：

// `p` points to the first character 'H' in an array of 6 characters 
// {'H', 'e', 'l', 'l', 'o', '\0'} forming the string literal. 
const char* p = "Hello"; 
// `q` holds the result of advancing `p` by one element. 
// That is, it points to character 'e' in the same array. 
const char* q = p + 1; 
// The sequence of characters, starting with that pointed by `q` 
// and ending with NUL character, is sent to the standard output. 
// That would be "ello" 
std::cout << q << std::endl;