Java字符数组错误

Question

我正在制作一种将字符转换为相应数字的方法，例如a = 1，b = 2 ...

我一直在从IDE接收关于我的字典数组声明的flak。我已阅读文档，但仍不知道如何改进。

感谢您提前给出的所有回复！ ：d

编辑： '' 格式化

public static int charNumTrans(char toBeTranslated){ 
    //Variable init 
    int translated = 0; 
    char guessedVariable; 

    //Checking if between a and i 
    if(toBeTranslated == 'a' || toBeTranslated == 'b' || toBeTranslated == 'c' || toBeTranslated == 'd' || toBeTranslated == 'e' 
    || toBeTranslated == 'f' || toBeTranslated == 'g' || toBeTranslated == 'h' || toBeTranslated == 'i'){ //Checking to see which array to use 

     char[] dictionary; 
     dictionary = new char {'0','.','1','a','2','b','3','c','4','d','5','e','6','f','7','g','8','h','9','i'}; 

     //chekcing between j and s 
    }else if(toBeTranslated == 'j' ||toBeTranslated == 'k' ||toBeTranslated == 'l' ||toBeTranslated == 'm' ||toBeTranslated == 'n' || 
      toBeTranslated == 'o' ||toBeTranslated == 'p' ||toBeTranslated == 'q' ||toBeTranslated == 'r' || toBeTranslated == 's'){//Checking to see if in between 
     dictionary[10] = {'0','j','1','k','2','l','3','m','4','n','5','o','6','p','7','q','8','r','9','s'}; 
    }else{//Everything else will be in this data set. 
     char[] dictionary = {'0','t','1','u','2','v','3','w','4','x','5','y','6','z'}; 
    } 

    guessedVariable = dictionary[1]; 
    while(dictionary[guessedVariable] != toBeTranslated){ 
     guessedVariable +=2; 
     } 

    // Assigns letter minus one of array. e.g. b = dictionary[5]. This will then assign dictionary[4] to translated. 
    translated = Character.getNumericValue(dictionary[guessedVariable-1]); 
    return translated; 
} 

Answer 1

首先，你是不是初始化你的数组以外的if语句，这意味着你的代码在最后将无法调用“dictionary”数组。其次，在你的场景中使用数组的问题是你有不同大小的数组。第三，就你如何初始化数组而言，正如人们已经指出的那样，你需要为你的数据集创建一个新的对象，例如， new char[] {...}。

完全解决你的问题，你可能要考虑这样的事情（我用同样的方法，以避免混淆初始化所有的数组的最简单的方法可能）：

public static int charNumTrans(char toBeTranslated){ 
    //Variable init 
    int translated = 0; 
    char guessedVariable; 

    //Checking if between a and i 
    if(toBeTranslated == 'a' || toBeTranslated == 'b' || toBeTranslated == 'c' || toBeTranslated == 'd' || toBeTranslated == 'e' 
|| toBeTranslated == 'f' || toBeTranslated == 'g' || toBeTranslated == 'h' || toBeTranslated == 'i'){ //Checking to see which array to use 

     char[] dictionary = {'0','.','1','a','2','b','3','c','4','d','5','e','6','f','7','g','8','h','9','i'}; 
     return findValue(dictionary); 

    //checking between j and s 
    }else if(toBeTranslated == 'j' ||toBeTranslated == 'k' ||toBeTranslated == 'l' ||toBeTranslated == 'm' ||toBeTranslated == 'n' || 
     toBeTranslated == 'o' ||toBeTranslated == 'p' ||toBeTranslated == 'q' ||toBeTranslated == 'r' || toBeTranslated == 's'){//Checking to see if in between 

     char[] dictionary = {'0','j','1','k','2','l','3','m','4','n','5','o','6','p','7','q','8','r','9','s'}; 
     return findValue(dictionary); 

    }else{//Everything else will be in this data set. 

     char[] dictionary = {'0','t','1','u','2','v','3','w','4','x','5','y','6','z'}; 
     return findValue(dictionary); 

    } 

} 

public static int findValue(char[] dictionary){ 
    guessedVariable = dictionary[1]; 
    while(dictionary[guessedVariable] != toBeTranslated){ 
     guessedVariable +=2; 
    } 

    // Assigns letter minus one of array. e.g. b = dictionary[5]. This will then assign dictionary[4] to translated. 
    translated = Character.getNumericValue(dictionary[guessedVariable-1]); 
    return translated; 
} 

Answer 2

变化 字典=新炭{ '0'， '1'， 'A'， '2'， 'B'， '3' ， 'C'， '4'， 'd'， '5'， 'E'， '6'， 'F'， '7'， 'G'， '8'， 'H'， '9'，”一世'};

到

dictionary = new char[] {'0','.','1','a','2','b','3','c','4','d','5','e','6','f','7','g','8','h','9','i'}; 

Answer 3

为了您的数组的声明，你缺少的[]当您指定的值要创建的数组对象 - 如此，例如，改变你的声明本：

char[] dictionary = new char[]{'0','t','1','u','2','v','3','w','4','x','5','y','6','z'}; 

另外，如果你正试图字母转换为数字等值，可我建议你投你已经传递给函数的char为int，然后从该值减去61？ 原因是是61对应的字符“一个”的Unicode字符表中的位置，将大大简化分配一个号码，你在传信。