使用ggplot2图形的默认填充颜色通过注释在R

Question

我想访问默认线或从ggplot2填充颜色，我不知道如何做到这一点。具体来说，在下面的代码中，您将在注释中看到green4,blue4和red4。这些是我的近似值我认为ggplot2正在使用。此外，如果此代码没有遵循最佳做法或可能受益于替代方法，请告知。

library(ggplot2) 
ggplot(data.frame(x = c(0, 1000)), aes(x)) + 
    stat_function(fun = dnorm, geom = "density", args = list(mean = 200, sd = 50), 
       aes(color="technology", fill="technology", alpha= 0.75)) + 
    stat_function(fun = dnorm, geom = "density", args = list(mean = 500, sd = 200), 
       aes(color="textiles", fill="textiles", alpha = 0.75)) + 
    stat_function(fun = dnorm, geom = "density", args = list(mean = 750, sd = 100), 
       aes(color="pharmaceuticals", fill="pharmaceuticals", alpha = 0.75)) + 
    labs(list(title="Fictious 'Density' Returns by Industry", x=NULL, y=NULL, color="Industry")) + 
    theme(legend.position="none") + 
    theme(axis.ticks = element_blank(), axis.text.y = element_blank()) + 
    annotate("text", label="technology", x=275, y=0.008, color="green4") + 
    annotate("text", label="textiles", x=500, y=0.0025, color="blue4") + 
    annotate("text", label="pharmaceuticals", x=835, y=0.0045, color="red4") 

Answer 1

使用ggplot_build，看到的场景背后究竟发生：

unique(sapply(ggplot_build(p)$data,'[[','colour')) 
    [,1]  [,2]  [,3]  
[1,] "#00BA38" "#619CFF" "#F8766D" 

unique(sapply(ggplot_build(p)$data,'[[','fill')) 
    [,1]  [,2]  [,3]  
[1,] "#00BA38" "#619CFF" "#F8766D"