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我想使用$ .getJSON从twitter api示例代码中浏览json数组,并使用jquery显示每个这些值?但它不是事先显示任何东西例如/帮助将不胜感激如何使用jQuery显示json数组?
我要显示的每个鸣叫用户长期&纬度在谷歌地图..
感谢
这JSON数组是http://dev.twitter.com/doc/get/geo/search
{
"result": {
"places": [
{
"name": "Twitter HQ",
"country": "The United States of America",
"country_code": "US",
"attributes": {
"street_address": "795 Folsom St"
},
"url": "http://api.twitter.com/1/geo/id/247f43d441defc03.json",
"id": "247f43d441defc03",
"bounding_box": {
"coordinates": [
[
[
-122.400612831116,
37.7821120598956
],
[
-122.400612831116,
37.7821120598956
],
[
-122.400612831116,
37.7821120598956
],
[
-122.400612831116,
37.7821120598956
]
]
],
"type": "Polygon"
},
"contained_within": [
{
"name": "San Francisco",
"country": "The United States of America",
"country_code": "US",
"attributes": {
},
"url": "http://api.twitter.com/1/geo/id/5a110d312052166f.json",
"id": "5a110d312052166f",
"bounding_box": {
"coordinates": [
[
[
-122.51368188,
37.70813196
],
[
-122.35845384,
37.70813196
],
[
-122.35845384,
37.83245301
],
[
-122.51368188,
37.83245301
]
]
],
"type": "Polygon"
},
"full_name": "San Francisco, CA",
"place_type": "city"
}
],
"full_name": "Twitter HQ, San Francisco",
"place_type": "poi"
}
]
},
"query": {
"url": "http://api.twitter.com/1/geo/search.json?query=Twitter+HQ&accuracy=0&autocomplete=false&granularity=neighborhood",
"type": "search",
"params": {
"granularity": "neighborhood",
"accuracy": 0,
"autocomplete": false,
"query": "Twitter HQ"
}
}
}
<!---- CODE --->
<!DOCTYPE html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>jQuery-TwitterAPI json</title>
<script type="text/javascript" src="jquery.js">
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#letter-b a').click(function() {
$.getJSON('geo.json', function(data) {
$('#tweetstuff').empty();
$.each(data.results, function(entryIndex, entry) {
var html = '<div class="entry">';
html += 'places' + entry.places + '</br>';
html += 'name' + entry.places.name + '</br>';
html += 'country' + entry.places.country + '</br>';
html += 'attributes' + entry.places.attributes + '</br>';
html += 'url' + entry.places.url + '</br>';
html += 'id' + entry.places.id + '</br>';
html += 'places' + entry.places.bounding_box + '</br>';
html += 'coordinates' + entry.places.coordinates + '</br>';
html += '</div>';
$('#dictionary').append(html);
});
});
return false;
});
});
</script>
</head>
<body>
<h1>jQuery-Twitter API Example</h1>
json
<div class="letters">
<div class="letter" id="letter-a">
<h3><a href="#">A</a></h3>
</div>
</div>
<div id="tweetstuff">
</div>
</body>
</html>
什么是不工作?你尝试了什么? – 2011-02-01 06:08:23
也许`$ .each(data.results.places,...` – 2011-02-01 17:37:35