我有一个JSON对象,它返回带有日期和时间的事件列表,我想为下一个事件时间添加一个计数器,但我不知道如何处理这个问题?从JSON数组计算javascript中的日期差异
基本上,我的JSON是这样的:
[{"name": "BAKER-CROSSROADS", "country": "USA", "lon": "165.25", "yield": "21", "lat": "11.58", "depth": ".027", "date": "1946/07/24 21:35:00", "id": "1"}, {"name": "VENUS", "country": "USA", "lon": "-116.2", "yield": "10", "lat": "37.19", "depth": ".03", "date": "1958/02/22 01:00:00", "id": "10", "fill": "green"}, {"name": "HATCHIE", "country": "USA", "lon": "-116.03", "yield": "20", "lat": "37.058", "depth": ".061", "date": "1963/02/08 16:00:01", "id": "100", "fill": "green"}, {"name": "CLIMAX:Upshot-Knothole", "country": "USA", "lon": "-116.0183", "yield": "61", "lat": "37.0875", "depth": "-.41", "date": "1953/06/04 11:14:57", "id": "1000", "fill": "red"}, {"name": "BRAVO:Castle", "country": "USA", "lon": "165.274", "yield": "15000", "lat": "11.698", "depth": "0", "date": "1954/02/28 18:45:00", "id": "1001", "fill": "red"}, ....
因此为每个对象:
{ “名”: “贝克十字路口”, “国”: “USA”, “LON”: “165.25”,“屈服”:“21”,“lat”:“11.58”,“深度”:“.027”,“日期”:“1946/07/24 21:35:00”,“id”: “1”}
{“name”:“VENUS”,“country”:“USA”,“lon”:“-116.2”,“yield”:“10”,“lat”:“37.19”, “深度”:“.03”,“日期”:“1958/02/22 01:00:00”,“id”:“10”,“fill”:“green”}
...
这里是读取JSON文件的代码:在这种情况下
this.loadNext = function() {
d3.json("./data/detonations.json", function(datum) {
for(var i = datum.length - 1; i >= 0; --i) {
var o = datum[i];
//console.log(o);
message = {
country: o.country
,date: o.date
,depth: o.depth
,lon: o.lon
,lat: o.lat
,type: o.type
,yield: o.yield
};
self.doSomething(message)
}
});
}
我想计算日期/时间差,所以“1958年至1902年的差额/ 22 01:00:00“和”1946/07/24 21:35:00“并将其传递给消息数组?
但this.loadNext读取json文件并通过它循环,所以我需要一个变量s1 = none;最初然后更新s1作为this.loadNext更新,是吗? – khinester