使用API​​数据创建动态表

Question

如何让我的表动态列出它从api中提取的所有值，atm只抽出1条记录并将其放入表中，其余数据放在表中

可能是一些非常小的，我在这里失踪，但不能把我的手指上

感谢您的帮助，非常赞赏。

<?php 
$trackingId = $_POST['trackingId']; 
if (isset($_POST['trackingId'])) { 
    $fetch = json_decode(file_get_contents(sprintf('apigoeshere', $trackingId))); 
    if ($fetch->status != 'OK') { 
     echo sprintf('Error: %s', $fetch->message); 
    } else { 
     //example how to access statistics variable 
     $inactiveAccounts = $fetch->statistics->inactiveAccounts; 
     echo sprintf('Inactive accounts: %d' . "<br /><br />", $inactiveAccounts); 
?> 
<table border="1"> 
     <tr> 
      <th>Account name</th> 
      <th>Level</th> 
     </tr> 
     <?php 
      //example how to display all accounts username 
      foreach ($fetch->accounts as $account) { 
    ?> 
     <tr> 
       <td><?php 
       echo $account->username; 
     ?></td> 
      <td><?php 
      echo $account->currentLevel; 
     ?></td> 
     </tr> 
</table> 
    <?php 
     } 
    } 
} 
?> 

Answer 1

Did not close foreach in right place。请使用此代码来代替

<?php 
$trackingId = $_POST['trackingId']; 
if (isset($_POST['trackingId'])) { 

    $fetch = json_decode(file_get_contents(sprintf('apigoeshere', $trackingId))); 

    if ($fetch->status != 'OK') { 
     echo sprintf('Error: %s', $fetch->message); 
    } else { 
     //example how to access statistics variable 
     $inactiveAccounts = $fetch->statistics->inactiveAccounts; 
     echo sprintf('Inactive accounts: %d' . "<br /><br />", $inactiveAccounts); 
?> 
<table border="1"> 
    <tr> 
     <th>Account name</th> 
     <th>Level</th> 
    </tr> 
    <?php 
     //example how to display all accounts username 
     foreach ($fetch->accounts as $account) { 
?> 
    <tr> 
     <td><?php 
      echo $account->username; 
?></td> 
     <td><?php 
      echo $account->currentLevel; 
?></td> 
    </tr> 
    <?php 
      } 
    ?> 
</table> 
<?php 

    } 
} 
?>