2016-08-11 53 views
0

我已经写了一个查询,它返回下列数据。SQL中RowNum的有条件选择

ID EmpFirstName EmpLastName RowNum 
1  X     Y  1 
2  A     B  1 
3  A     B  2 

现在我想要RowNum> 1的所有记录。例如,在这种情况下,我需要输出2和3记录。

如果我把条件RowNum >1然后我只会得到第三条记录,但我也想要2。

+0

如果第二条记录有'RowNum' ='1',那么为什么你要在你的结果集?这听起来与我矛盾。 –

+0

其实@TimBiegeleisen如果设置有任何重复的记录,那么我需要完整的记录信息。原始数据集中有很多字段,显然重复将被删除,但是要做出决定,两个记录都需要输出。如果我选择'RowNum = 2',那么决定是否删除第2条记录或第1条记录。 –

+0

我看到重复的第一行和第二行,但是它们的'RowNum'值仍然小于1.为什么包含它们? –

回答

1

假设你的查询是这样的:

select ID, EmpFirstName, EmpLastName, 
ROW_NUMBER() OVER (PARTITION BY EmpFirstName, EmpLastName ORDER BY ID) AS RowNum 
FROM aTable 

这是用来过滤掉任何重复值的经典查询。

为了有效地选择所有重复值的记录,我可以建议使用COUNT()窗口功能:

;with a as (
    select ID, EmpFirstName, EmpLastName, 
    ROW_NUMBER() OVER (PARTITION BY EmpFirstName, EmpLastName ORDER BY ID) AS RowNum, 
    COUNT(*) OVER (PARTITION BY EmpFirstName, EmpLastName) AS cnt 
    FROM aTable 
) 
SELECT * FROM a where cnt > 1 
ORDER BY EmpFirstName, EmpLastName 

为了测试它使用此查询:

drop table #tmp 
CREATE table #tmp (ID int , EmpFirstName varchar(10) , EmpLastName varchar(10)) 
go 
INSERT INTO #tmp VALUES 
    (1,'X','Y') 
    ,(2,'A','B') 
    ,(3,'A','B') 
    ,(4,'A','C') 
    ,(5,'B','C') 
    ,(6,'B','C') 


;with a as (
    select ID, EmpFirstName, EmpLastName, 
    ROW_NUMBER() OVER (PARTITION BY EmpFirstName, EmpLastName ORDER BY ID) AS RowNum, 
    COUNT(id) OVER (PARTITION BY EmpFirstName, EmpLastName) AS cnt 
    FROM #tmp 
) 
SELECT * FROM a where cnt > 1 
ORDER BY EmpFirstName, EmpLastName 

结果:

ID   EmpFirstName EmpLastName RowNum    cnt 
----------- ------------ ----------- -------------------- ----------- 
2   A   B   1     2 
3   A   B   2     2 
5   B   C   1     2 
6   B   C   2     2 
+0

我喜欢逻辑'COUNT(*)OVER(PARTITION BY EmpFirstName,EmpLastName)AS cnt',但它没有工作..它在计数结束EmpFirstName而不考虑姓氏:( –

+0

适用于我:'drop table #tmp CREATE table #tmp(ID int,EmpFirstName varchar(10),EmpLastName varchar(10)) go INSERT INTO #tmp VALUE (1,'X','Y') ,(2,'A',' B') ,(3,'A','B') ,(4,'A','C') ,(5,'B','C') ,(6''B' ,'C') ; with a( select ID,EmpFirstName,EmpLastName, ROW_NUMBER()OVER(PARTITION BY EmpFirstName,Emp (*)OVER(PARTITION BY EmpFirstName,EmpLastName)AS cnt FROM #tmp ) )SELECT * FROM a where cnt> 1' – cha

+0

好吧,我想我觉得为什么它似乎你这是由EmpFirstName计数,这是因为你的结果集是未排序的。将'ORDER BY EmpFirstName,EmpLastName'添加到查询的末尾,您将得到正确的结果 – cha

0

我制作样本数据并使用此查询

CREATE table #tmp (ID int , EmpFirstName varchar(10) , EmpLastName varchar(10) ,RowNum int) 
INSERT INTO #tmp VALUES 
    (1,'X','Y',1) 
    ,(2,'A','B',1) 
    ,(3,'A','B',2) 

SELECT ID,EmpFirstName,EmpLastName,RowNum 
FROM (
    SELECT * 
     ,ROW_NUMBER() OVER (ORDER BY ID) AS [NEWrownum] 
    FROM #tmp 
) q 
WHERE q.NEWrownum > 1 
0

试试这个,

DECLARE @Result TABLE (ID INT, EmpFirstName VARCHAR(10), EmpLastName VARCHAR(10), RowNum INT) 

INSERT INTO @Result 
VALUES 
    (1, 'X', 'Y', 1) 
    ,(2, 'A', 'B', 1) 
    ,(3, 'A', 'B', 2) 

SELECT r1.* 
FROM @Result r1 
INNER JOIN (SELECT *  -- get duplicate records 
      FROM @Result 
      WHERE RowNum = 2     
      ) as r2 ON r1.EmpFirstName = r2.EmpFirstName 
        AND r1.EmpLastName = r2.EmpLastName