如何处理来自flickr的xml响应

Question

import flickrapi 
from xml.etree import ElementTree as ET 
from lxml import etree 

flickr = flickrapi.FlickrAPI(api_key,secret=api_secret) 
r = flickr.photos_search(tags='e-waste', has_geo="1", per_page='100') 
tree = ET.ElementTree(r) 

xml_input = etree.parse("response_clean.xml") 
transform = etree.XSLT(xslt_root) 
links = str(transform(xml_input)) 

这个小脚本的想法是从Flickr获取xml响应，然后使用xsl文件进一步处理它。

我想转换r对象（其是lxml.etree._Element类型） 到xml_input（的lxml.etree._ElementTree类型）。

我用tree = ET.ElementTree(r)，但结果是xml.etree.ElementTree.ElementTree。

我看到这不完全相同，但我不明白区别。

r如何转换为xml_input？

Answer 1

该代码创建xml.etree.ElementTree.ElementTree，因为ET中对应的import语句引用xml.etree.ElementTree。您应该使用etree.ElementTree代替，它是从lxml导入的：

>>> from xml.etree import ElementTree as ET 
>>> from lxml import etree 
>>> raw ='''<root></root>''' 
>>> r = etree.fromstring(raw) 
>>> root = etree.ElementTree(r) 
>>> type(r) 
<type 'lxml.etree._Element'> 
>>> type(root) 
<type 'lxml.etree._ElementTree'>