2016-10-21 46 views
0

我在我的模型中有两个函数,我想在我的模型中调用其他模型,但实际上是将错误数组转换为字符串。 这是我的代码:如何在一个模型中调用其他模型?

public function get_detail_activity() 
{ 
    $status=$activity;//call function model activity 
    $query=$this->db->query("SELECT 
    t_trx_activity.activity_id FROM t_trx_activity 
    JOIN t_trx_activity_detail ON 
    t_trx_activity_detail.activity_id =t_trx_activity.activity_id 
    WHERE t_trx_activity.activity_id = '".$status."' //function put here"); 

    if($query->num_rows()>0) 
    { 
     return $query->result(); 
    } 
    else 
    { 
     return array(); 
    } 

public function activity() 
{ 
    $query=$this->db->query("SELECT t_trx_activity.activity_id 
     FROM t_trx_activity 
     ORDER BY 
     t_trx_activity.activity_id DESC LIMIT 1"); 
    $nik=$this->session->userdata('nik'); 

    if($query->num_rows()>0) 
    { 
     return $query->result(); 
    } 
    else 
    { 
     return array(); 
    } 
} 

如何调用函数等模型在一个模型?

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我不遵守你正试图在这里做...你能有另一个去试图解释你想要什么实现? – TimBrownlaw

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我想要显示来自get_detail_activity的数据和其中(来自函数活动) –

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因此,这是相同的模型还是不同的模型? –

回答

0

你没有正确调用该函数,请尝试以下,

public function get_detail_activity() 
{ 
    $status= $this->activity();//call function model activity 
    $query=$this->db->query("SELECT 
      t_trx_activity.activity_id FROM t_trx_activity 
      JOIN t_trx_activity_detail ON 
      t_trx_activity_detail.activity_id =t_trx_activity.activity_id 
      WHERE t_trx_activity.activity_id = '".$status."'"); 
    if($query->num_rows()>0) 
    { 
     return $query->result_array(); 
    } 
    else 
    { 
     return array(); 
    } 
} 


public function activity() 
{ 
    $query=$this->db->query("SELECT t_trx_activity.activity_id 
     FROM t_trx_activity 
     ORDER BY 
     t_trx_activity.activity_id DESC LIMIT 1"); 
     $nik=$this->session->userdata('nik'); 

    if($query->num_rows()>0) 
    { 
     return $query->row()->activity_id; 
    } 
    else 
    { 
     return 0; 
    } 
} 
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错误数组到字符串转换 –

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在哪行?我很确定错误还显示行号? –

+0

@ i.one:检查我更新的ans –

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