SQL针对Oracle的COMAND

Question

MYSQL：

SELECT * FROM book ORDER BY $sidx $sord LIMIT $start , $limit; 

我如何把它变成甲骨文？

Answer 1

你必须使用rownum财产，但你必须把它应用到结果集已经下令，你需要从内部查询（信贷鲍勃·贾维斯和丹尼尔Hilgarth传递：您在注释中给出他们的解释和链接以及）。它应该是这样的：

SELECT * FROM 
(SELECT b.*, rownum as row_num FROM book b ORDER by $sidx $sord) 
WHERE row_num BETWEEN $start AND $start + $limit; 

Answer 2

10克勇往直前

WITH CTE AS(SELECT b.*, Row_Number() OVER(ORDER BY SIDX,SORD) AS Rn FROM BOOK b) 
SELECT * 
FROM CTE 
WHERE Rn BETWEEN STARTLIMIT AND ENDLIMIT 

Answer 3

我不熟悉Oracle语法，但你可以使用ROW_NUMBER()功能排名中的行，然后选择那些具有rank BETWEEN @start and @limit ：

SELECT * 
    FROM 
    (
     select *, 
      ROW_NUMBER() OVER (ORDER BY ID DESC) AS rank 
     FROM book 
    ) 
    WHERE rank BETWEEN @start AND @end 
    /* OR 
    WHERE BETWEEN ((@PageNum - 1) * @PageSize + 1) 
    AND (@PageNum * @PageSize) 
    /* 

Answer 4

select * from(
select rownum as row_num, id from t 
) 
where row_num between :start and :start+:limit