2010-03-01 37 views
8

我正在尝试在mysql和glassfish中使用hibernate实体管理器。我得到尝试使用JTA数据源时,出现以下错误:hibernate,mysql,glassfish v3和JTA数据源

Caused by: org.hibernate.HibernateException: The chosen transaction strategy requires access to the JTA TransactionManager 
     at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:376) 
     at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1367) 
     at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:858) 
     at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:733) 
     ... 37 more 

这里是如何我已经配置我的persistence.xml

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> 
    <persistence-unit name="myPU" transaction-type="JTA"> 
    <provider>org.hibernate.ejb.HibernatePersistence</provider> 
    <jta-data-source>jdbc/mysql</jta-data-source> 
    <class>com.my.shared.entity.MyFile</class> 
    <class>com.my.shared.entity.MyRole</class> 
    <class>com.my.shared.entity.MyUser</class> 
    <exclude-unlisted-classes>true</exclude-unlisted-classes> 
    <properties> 
     <property name="hibernate.hbm2ddl.auto" value="create-drop"/> 
     <property name="hibernate.show.sql" value="true" /> 
    </properties> 

然而,当我配置非jta datasource,它工作正常

<?xml version="1.0" encoding="UTF-8"?> 
    <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> 
     <persistence-unit name="myPU" transaction-type="JTA"> 
     <provider>org.hibernate.ejb.HibernatePersistence</provider> 
     <non-jta-data-source>jdbc/mysql</non-jta-data-source> 
     <class>com.my.shared.entity.MyFile</class> 
     <class>com.my.shared.entity.MyRole</class> 
     <class>com.my.shared.entity.MyUser</class> 
     <exclude-unlisted-classes>true</exclude-unlisted-classes> 
     <properties> 
      <property name="hibernate.hbm2ddl.auto" value="create-drop"/> 
      <property name="hibernate.show.sql" value="true" /> 
     </properties> 
</persistence-unit> 
</persistence> 

这一切都很好d不错,但我真的想用:

em.persist(myObject); 

代替:

em.getTransaction().begin(); 
em.persist(myObject); 
em.getTransaction().commit(); 

我错过了与Hibernate配置的东西,或者是它甚至有可能使用JTA数据源?

回答

11

对于您的配置来说,默认情况下使用容器管理的事务。在这种情况下,您需要定义一种事务同步方式,以便通知持久层(并可以更新二级缓存)。所以,你需要定义manager_lookup_class属性如下:

// For GlassFish: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.SunONETransactionManagerLookup 
// For WebSpere: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.WebSphereExtendedJTATransactionLookup 
// For JBoss: 
hibernate.transaction.manager_lookup_class=org.hibernate.transaction.JBossTransactionManagerLookup 
// For OpenEJB: 
hibernate.transaction.manager_lookup_class=org.apache.openejb.hibernate.TransactionManagerLookup 

而且你必须标记访问数据层的“交易”的经营方式。为此,您需要使用@javax.ejb.TransactionAttribute(REQUIRED)标记它们(有关此注释的更多信息,请参见here)。

您还可以选择切换到Bean管理事务。你可以这样做:

hibernate.transaction.factory_class=org.hibernate.transaction.JTATransactionFactory

那么这个bean负责启动/停止交易:

org.hibernate.Session session = ...; 
org.hibernate.Transaction tx = null; 
try { 
    tx = session.beginTransaction(); 
    session.createQuery(...); // do some staff 
    tx.commit(); 
} catch (HibernateException e) 
{ 
    if (tx != null) { 
     tx.rollback(); 
    } 
} 
+2

好了,所以我加的到我的persistence.xml。现在它“持续”没有错误,但它永远不会被提交到数据库。 – KevMo 2010-03-01 23:54:23

+0

@KevMo:您不需要像使用CMT一样声明性地使用'em.getTransaction()。begin();'来执行事务。我希望,你已经用'@ Transactional'标记了你的bean方法? – 2010-03-02 08:11:56

+0

Ops,对不起,你没有使用Spring :)然后按照我的答案。 – 2010-03-02 12:42:03