如何在sql中找到全名匹配（顺序无关紧要）对于

Question

例如：'Swati Prakash Phapale'则可能的条件是'prakash swati phapale'，'swati phapale prakash'，prakash swati phapale'或多重排列

Answer 1

DECLARE @fName varchar(max) =ltrim(rtrim(isnull('swati',''))) 
DECLARE @mName varchar(max) =ltrim(rtrim(isnull(' phapale',''))) 
DECLARE @lName varchar(max) =ltrim(rtrim(isnull(' prakash',''))) 

DECLARE @FullName varchar(max), @Split char(1)=' ' ,@X1 xml,@i int=0 
if len(@mName)!=0 
set @FullName = @fName +' ' + @mName +' '+@lName 
else 
begin 
set @FullName = @fName +' '+@lName 
end 
IF len(@FullName)=0 BEGIN 
SET @FullName = 'null' END DECLARE @hit AS varchar(MAX)='', 
           @EmptyGuid UniqueIdentifier='00000000-0000-0000-0000-000000000000' 
SELECT @X1 = CONVERT(xml,' <root> <s>' + REPLACE(@FullName,@Split,'</s> <s>') + '</s> </root> ') 
declare @tmp1 as table(name varchar(max)) 
declare @tmp2 as table(RowNo bigint,name varchar(max)) 
insert into @tmp1(name)select * from (SELECT name = T.c.value('.','varchar(max)')FROM @X1.nodes('/root/s') T(c)) T 
declare @num as int; 
set @num = (select count(*) from @tmp1); 
-- Permutations of #t 
with T (name, level) as(select convert(varchar(max), name), level=1 from @tmp1 union all select convert(varchar(max),t1.name+' '+T.name),level+1 
from @tmp1 t1,T where level < @num and charindex(t1.name,T.name) = 0) 
insert into @tmp2(RowNo,name)select RowNo = Row_Number() over (order by name), name from T where level = @num 

SET @hit= isnull((select tc.name from @tmp2 t inner join **YourTableName** tc on t.name=tc.name),'') 

SET @hit=concat('Full Name Matched with:',@hit) 
IF len(@hit)>0 --@hit<>'' 

SET @hit=concat('FullName Matched with:',@hit) 
Else 
BEGIN 
SET @hit=concat('No FullName Matched with:',@hit) 
end 
print @hit 

Note : In 'YourTableName', 'Name' column contain fullname