休眠抛出StreamCorruptedException：无效的流头

Question

我有这样一个类，

class SampleClass implements Serializable { 
    String name; 
    Serializable fieldName; 
} 

而另一个类一样，

class AnotherClass implements Serializable { 
    SampleClass sampleClass; 
} 

其中两个类都有自己的getter和setter方法。

在主类中，我从getter函数获取sampleClass变量，并尝试使用sampleClass对象。但是当我使用它时，我遇到了像could not deserialize这样的错误。

如何访问SampleClass的成员，或者我们是否有Serializable类型的现场成员？

谢谢。

---

编辑： 我使用休眠，它使用许多人aemploye和aaddress表之间的一个关系。

我为上述两个表创建了Hibernate配置文件和net beans中的逆向工程文件。

然后我生成了POJO类。

类和xml是：

Aaddress.hbm.xml

<hibernate-mapping> 
<class name="hibernatetutor.tablebeans.Aaddress" table="aaddress" schema="public"> 
    <id name="sno" type="int"> 
     <column name="sno" /> 
     <generator class="assigned" /> 
    </id> 
    <property name="street" type="serializable"> 
     <column name="street" /> 
    </property> 
    <set name="aemployes" inverse="true"> 
     <key> 
      <column name="address" /> 
     </key> 
     <one-to-many class="hibernatetutor.tablebeans.Aemploye" /> 
    </set> 
</class> 

Aemploye.hbm.xml

<hibernate-mapping> 
<class name="hibernatetutor.tablebeans.Aemploye" table="aemploye" schema="public"> 
    <id name="id" type="int"> 
     <column name="id" /> 
     <generator class="assigned" /> 
    </id> 
    <many-to-one name="aaddress" class="hibernatetutor.tablebeans.Aaddress" fetch="select"> 
     <column name="address" /> 
    </many-to-one> 
    <property name="name" type="string"> 
     <column name="name" /> 
    </property> 
</class> 

Aaddress.java

public class Aaddress implements java.io.Serializable { 

    private int sno; 
    private Serializable street; 
    private Set aemployes = new HashSet(0); 

    public int getSno() { 
     return this.sno; 
    } 

    public void setSno(int sno) { 
     this.sno = sno; 
    } 

    public Serializable getStreet() { 
     return this.street; 
    } 

    public void setStreet(Serializable street) { 
     this.street = street; 
    } 

    public Set getAemployes() { 
     return this.aemployes; 
    } 

    public void setAemployes(Set aemployes) { 
     this.aemployes = aemployes; 
    } 
} 

Aemploye.java

public class Aemploye implements java.io.Serializable { 

    private int id; 
    private Aaddress aaddress; 
    private String name; 

    public int getId() { 
     return this.id; 
    } 

    public void setId(int id) { 
     this.id = id; 
    } 

    public Aaddress getAaddress() { 
     return this.aaddress; 
    } 

    public void setAaddress(Aaddress aaddress) { 
     this.aaddress = aaddress; 
    } 

    public String getName() { 
     return this.name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 
} 

Main.java

private void getData() { 
    Session session = HibernateUtils.getInstance().openSession(); 
    Query query = session.createQuery("from Aemploye where id=:id"); 
    query.setParameter("id", 1); 
    Aemploye a = (Aemploye) query.uniqueResult(); 
    Aaddress a1 = a.getAaddress(); 
    System.out.println(a1.getStreet()); 
} 

的错误是：

org.hibernate.type.SerializationException: could not deserialize 
    at org.hibernate.util.SerializationHelper.deserialize(SerializationHelper.java:217) 
    at org.hibernate.util.SerializationHelper.deserialize(SerializationHelper.java:240) 
    at org.hibernate.type.SerializableType.fromBytes(SerializableType.java:82) 
    at org.hibernate.type.SerializableType.get(SerializableType.java:39) 
    at org.hibernate.type.NullableType.nullSafeGet(NullableType.java:163) 
    at org.hibernate.type.NullableType.nullSafeGet(NullableType.java:154) 
    at org.hibernate.type.AbstractType.hydrate(AbstractType.java:81) 
    at org.hibernate.persister.entity.AbstractEntityPersister.hydrate(AbstractEntityPersister.java:2096) 
    at org.hibernate.loader.Loader.loadFromResultSet(Loader.java:1380) 
    at org.hibernate.loader.Loader.instanceNotYetLoaded(Loader.java:1308) 
    at org.hibernate.loader.Loader.getRow(Loader.java:1206) 
    at org.hibernate.loader.Loader.getRowFromResultSet(Loader.java:580) 
    at org.hibernate.loader.Loader.doQuery(Loader.java:701) 
    at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:236) 
    at org.hibernate.loader.Loader.loadEntity(Loader.java:1860) 
    at org.hibernate.loader.entity.AbstractEntityLoader.load(AbstractEntityLoader.java:48) 
    at org.hibernate.loader.entity.AbstractEntityLoader.load(AbstractEntityLoader.java:42) 
    at org.hibernate.persister.entity.AbstractEntityPersister.load(AbstractEntityPersister.java:3044) 
    at org.hibernate.event.def.DefaultLoadEventListener.loadFromDatasource(DefaultLoadEventListener.java:395) 
    at org.hibernate.event.def.DefaultLoadEventListener.doLoad(DefaultLoadEventListener.java:375) 
    at org.hibernate.event.def.DefaultLoadEventListener.load(DefaultLoadEventListener.java:139) 
    at org.hibernate.event.def.DefaultLoadEventListener.onLoad(DefaultLoadEventListener.java:98) 
    at org.hibernate.impl.SessionImpl.fireLoad(SessionImpl.java:878) 
    at org.hibernate.impl.SessionImpl.immediateLoad(SessionImpl.java:836) 
    at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:66) 
    at org.hibernate.proxy.AbstractLazyInitializer.getImplementation(AbstractLazyInitializer.java:111) 
    at org.hibernate.proxy.pojo.cglib.CGLIBLazyInitializer.invoke(CGLIBLazyInitializer.java:150) 
    at hibernatetutor.tablebeans.Aaddress$$EnhancerByCGLIB$$44bec229.getStreet(<generated>) 
    at hibernatetutor.Main.getData(Main.java:33) 
    at hibernatetutor.Main.main(Main.java:24) 
Caused by: java.io.StreamCorruptedException: invalid stream header 
    at java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:753) 
    at java.io.ObjectInputStream.<init>(ObjectInputStream.java:268) 
    at org.hibernate.util.SerializationHelper$CustomObjectInputStream.<init>(SerializationHelper.java:252) 
    at org.hibernate.util.SerializationHelper.deserialize(SerializationHelper.java:209) 
    ... 29 more 

Answer 1

使用吸气不涉及诗里亚除非你有一些非常不寻常的框架来做到这一点。

我建议你看看确切的堆栈跟踪（并在问题中发布）并查看异常实际发生的位置。

Answer 2

我想你的类，它的工作对我来说：

import java.io.*; 

class SampleClass implements Serializable { 
     String name; 
     Serializable fieldName; 
} 

class AnotherClass implements Serializable { 
     SampleClass sampleClass; 
} 

public class Ser { 
    public static void main(String argv[]) 
     throws Exception 
    { 
     SampleClass s = new SampleClass(); 
     s.name = "name"; 
     s.fieldName = "fieldName"; 

     AnotherClass a = new AnotherClass(); 
     a.sampleClass = s; 

     // serialize the classes to a byte array 
     ByteArrayOutputStream os = new ByteArrayOutputStream(); 
     ObjectOutputStream oos = new ObjectOutputStream(os); 
     oos.writeObject(a); 
     oos.close(); 

     // deserialize the classes from the byte array 
     ObjectInputStream is 
      = new ObjectInputStream(
        new ByteArrayInputStream(os.toByteArray())); 
     a = (AnotherClass)is.readObject(); 
     is.close(); 

     // print something 
     System.out.println(a.sampleClass.name); 
    } 
} 

你能后引起问题的确切的代码？

Answer 3

在这两个问题的基础上，一些来自注释部分的信息，相信你的烦恼是由以下原因造成的：

您有选择的街道某种原因属性为类型序列化的。在您的表格中，此列已被定义为类型TEXT。 Hibernate可能会设法将序列化数据保存到列中，但数据库可能无法保持不变。因此，在检索时，现在乱码的序列化无法反序列化。

解决方案是，作为PetrPudlák指出的，以使您的映射正确。如果您选择了合适的二进制类型，例如BYTEA，那么您将能够保存二进制数据不变。检索应该工作。

这不是正确的解决方案恕我直言，这将是首先在您的Java代码中选择合适的数据类型。将街道的类型设置为可串行化对查看您的代码的任何人都很困惑。 String可能会更有意义，并且也适用于列类型TEXT。