2014-10-10 54 views
-1

我有2个表
表1结构:日志]
用户ID ||点击||日期|| XXX || XXX |||
表2结构:[用户]
username ||电子邮件||日期|| XXX || XXX |||
如何收集从使用两个表中的数据连接

我想这样

用户名显示的数据,COUNT(点击)

我使用下面的查询。

SELECT `user.username`,`userid`, COUNT(`userid`) as `total` 
FROM `logs` 
    INNER JOIN user ON logs.userid=user.userid 
ORDER BY total DESC 
LIMIT 5 

请quide

第一答复后,我体改查询和应用。查阅全文,就像这样

$sqlptcwall=mysql_query("SELECT user.username, COUNT(ptcwalllogs.userid) AS total FROM logs INNER JOIN user ON user.userid = ptcwalllogs.userid GROUP BY user.username ORDER BY COUNT(ptcwalllogs.userid) DESC 
LIMIT 5"); 



<?php 
echo "</tr>"; 
     while($row = mysql_fetch_array($sqlptcwall)) 
     { 
echo "<tr> "; 
    echo "<td>" .$row[userid] . "</td>"; 
    echo "<td>" .$row[total] . "</td>"; 
    } 
echo "</tr> " ; 
?> 

错误: mysql_fetch_array()预计参数1是资源,布尔给定在

+0

只需添加一个'group by [some_field]' – Barranka 2014-10-10 18:02:27

回答

1
SELECT user.username, COUNT(user.userid) AS total 
FROM logs 
    INNER JOIN user ON user.userid = logs.userid 
GROUP BY user.username 
ORDER BY COUNT(user.userid) DESC 
LIMIT 5 
+0

edit t他质疑我收到的更多细节和错误 – nasima 2014-10-10 18:15:40

+0

您现在的问题不在原始问题的范围之内。仔细阅读错误消息并检查您的数据访问代码。 – Namrehs 2014-10-10 18:17:40

+0

发现我的错误:) – nasima 2014-10-10 18:22:58